9514 1404 393
Answer:
a) 12
b) y +5 = 12(x +2)
Step-by-step explanation:
The slope of a function is its derivative.
a) The slope of y = x^3 +3 at any point is y' = 3x^2. So, at the point where x=-2, the slope of the curve is ...
m = 3(-2)^2 = 12 . . . . slope at (-2, -5)
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b) The equation of the tangent line is most easily written using the point-slope form of the equation of a line.
y -k = m(x -h) . . . . . line with slope m through point (h, k)
y +5 = 12(x +2) . . . . line with slope 12 through point (-2, -5)
Slope for (x₁, y₁) and (x₂, y₂): (-3, 0) and (2, 7)
Slope: (y₂ -y₁) / (x₂ -x₁)
Slope: ( 7 - 0) / (2 - -3) = 7/(2 + 3)
<span>Slope = 7/5
</span>
The answer is 28
Hope this helped!!
Answer:
Step-by-step explanation:
for example
We have to write the polynomial P(x) = 5x^3 -2x^2 + 5x - 2 as a product of linear factors.
P(x) = 5x^3 -2x^2 + 5x - 2
=> P(x) = x^2( 5x - 2) + 1( 5x - 2)
=> P(x) = (x^2 + 1)(5x - 2)