Answer:
EF=35
EG=22
Step-by-step explanation:
EF
7y-14=2y+21
5y=35
y=7
EF=7(7)-14=49-14=35
EG
15x+7=12x+10
3x=3
x=1
EG=15(1)+7=15+7=22
Answer:
y = - 16t² + 55.6t + 6
Step-by-step explanation:
Using y - y₀ = vt - 1/2gt² where g = 32 ft/s², and v the velocity of the football
So y = y₀ + vt - 1/2 × (32 ft/s²)t²
y = y₀ + vt - 16t² where y₀ = 6.5 ft
y = 6 + vt - 16t²
Now, when t = 3.5 s, that is the time the teammate catches the ball after the quarterback throws it, y = 5 ft. Substituting these into the equation, we have
5 = 6.5 + v(3.5 s) - 16(3.5 s)²
5 = 6.5 + 3.5v - 196
collecting like terms, we have
5 - 6.5 + 196 = 3.5v
194.5 = 3.5v
v = 194.5/3.5 = 55.57 ft/s ≅ 55.6 ft/s
So, substituting v into y, our quadratic model is
y = 6 + 55.6t - 16t²
re-arranging, we have
y = - 16t² + 55.6t + 6
The 1 slide it is intersecting the second slide is the 4x-y=5 slide 3 is the same and 4th slide is different
Student P:
They messed up in step 1 because they made the 7.75 positive instead of negative, which causes the entire solution to be wrong
Student Q:
They were correct up until step 3. They didn't take all the negatives out of the equation (ex. -(3.5+7.75+29.67)).
Complete set:
From the picture, it looks like the original problem was
-2.5(1.4+3.1)+6.9(-4.3)
Step 1: multiply
1.4(-2.5)+3.1(-2.5)+6.9(-4.3)
Step 2: subtract (add?) them all together
-3.5-7.75-29.67
Step 3 should equal -40.92
Answer:
c/-9+6=14
c/-9=14-6
c/-9=8
c=8×(-9)
c= -72
Therefore the answer is (b)
