Answer:
Difference between the approximation and the actual value of f′(0.5) is 0.4330
Step-by-step explanation:
As complete question is not give, so considering the most relevant question to given statement in Fig below.
from table
x 0 1
f(x) 1 2
f'(0.5)=?
from numerical differentiation
Given function is
Differentiating w.r.to x
Difference between the approximation and the actual value of f′(0.5) is 0.4330
I believe it would be 4 1/10 ,4.104, 104/25, 4.74
The answer is 8.
half of 16 is 8
Answer: the equation of this parallel line would be: Answer: y = 5x - 6
Step-by-step explanation:
Slope of the parallel lines are same
So, m= 5
(3,9)
Equation: y - y1 = m(x -x1)
y - 9 = 5(x - 3)
y - 9 = 5x - 3*5
y -9 = 5x -15 {add 9 to both sides}
y - 9 + 9 = 5x - 15 + 9
y = 5x - 6
plz brainliest
Answer:
Its A trust me i got it right
Step-by-step explanation: