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Gnom [1K]
3 years ago
9

80,673,854 in expanded form

Mathematics
1 answer:
stiv31 [10]3 years ago
8 0

8398.21

make sure you add the 80 then divide 673 & u add 2 cakes and see how many cupckakes sally has all together and that's the answer.

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Find each measurement indicated. Round your answers to the nearest tenth.
Crazy boy [7]

Answer:

A

Step-by-step explanation:

Find AB using the Law of Sine:

\frac{AB}{sin(C)} = \frac{AC}{sin(B)}

Thus:

\frac{AB}{sin(40)} = \frac{47}{sin(103)}

Multiply both sides by sin(40)

\frac{AB}{sin(40)}*sin(40) = \frac{47}{sin(103)}*sin(40)

AB = \frac{47*Sin(40)}{sin(103)}

AB = 31.0056916 ≈ 31.0 cm (nearest tenth)

6 0
3 years ago
Math question I need help with
Greeley [361]
F(x) = (x - 4) (x^2 + 4) would be your answer.
4 0
3 years ago
Find the domain and range of 1/t+2
kotegsom [21]

Answer:

Domain = (-∞, -2) ∪ (-2, ∞).

Range =  (-∞, 0) ∪ (0, ∞).

Step-by-step explanation:

t can't have the value -2 because that would make  1/(t + 2) = 1/0 which is undefined.

So the domain is All real values of t. except t = -2.

As t approaches infinity or negative infinity  f(t) approaches  zero, and as t approaches -2 from below or above f(t) approaches negative infinity or positive infinity.

8 0
3 years ago
13. For what value of b would the following system of equations have an infinite number of solutions?
tiny-mole [99]

Answer:

b=2

Step-by-step explanation:

we have

9x+12y=21 -----> equation A

6x+8y=7b ----> equation B

we know that

If the system of equations have an infinite number of solutions then the equation A must be equal to the equation B

Multiply equation B by 1.5 both sides

1.5*[6x+8y[=7b*1.5

9x+12y=10.5b ----> equation C

Compare equation A and equation C

9x+12y=21 -----> equation A

9x+12y=10.5b ----> equation C

For the equations to be equal it must be fulfilled that

21=10.5b

solve for b

b=21/10.5

b=2

5 0
4 years ago
If arc SQ = 84° and ∠RPS = 26°, what is the measure of arc RS? need answer asap thank you
Lera25 [3.4K]

Answer:

arc\ RS=136\°

Step-by-step explanation:

we know that

The measurement of the external angle is the semi-difference of the arcs which comprises

In this problem

m∠RPS=26\° ------> external angle

so

m∠RPS=\frac{1}{2}(arc\ RS-arc\ SQ)

we have

m∠RPS=26\°

arc\ SQ=84\°

substitute the values

26\°=\frac{1}{2}(arc\ RS-84\°)

Solve for arc RS

52\°=(arc\ RS-84\°)

arc\ RS=52\°+84\°=136\°

3 0
3 years ago
Read 2 more answers
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