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1 year ago

What is the sum of 1/4 and 5/12 ?

Mathematics

1 answer:

likoan [24]1 year ago

6 0

Answer: 8/12

Step-by-step explanation:

1/4 times 3 will give you 3/12 and add 5/12

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Someone pls help me I will make you as brain

Y_Kistochka [10]

Answer:

B: shift vertically up by 3

Step-by-step explanation:

I suggest using desmos graphing for future questions like these

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2 years ago

On a number line, what number is 2/3 of the way from 7 to 13?

notka56 [123]

Answer:

That would be about 11.667

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2 years ago

How do you write 32,005,008 in expanded form

Karolina [17]

To write 32,005,008 in expanded form, you write it out like this: <span>32,005,008 = 30,000,000 + 2,000,000 + 5,000 + 8.

I know this because I learned it in 3rd grade at school.

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2 years ago

Read 2 more answers

What is the solution to 6x + 1 = 4x -3

PSYCHO15rus [73]

6x +1 = 4x -3

6x = 4x -4

2x = -4

x =-2

your answer is -2

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2 years ago

Read 2 more answers

A plane takes off from an airport and flies at a speed of 400km/h on a course of 120° for 2 hours. the plane then changes its co

butalik [34]

Answer:

Distance from the airport = 894.43 km

Step-by-step explanation:

Displacement and Velocity

The velocity of an object assumed as constant in time can be computed as

$\displaystyle \vec{v}=\frac{\vec{x}}{t}$

Where $\vec x$ is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

$\displaystyle \vec{x}=\vec{v}.t$

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as

$\displaystyle \vec{v_1}=$

$\displaystyle \vec{v_1}=\ km/h$

The displacement of the plane in 2 hours is

$\displaystyle \vec{x_1}=\vec{v_1}.t_1=.(2)$

$\displaystyle \vec{x_1}=km$

Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are

$\displaystyle \vec{v_2}=$

$\displaystyle \vec{v_2}=km/h$

The displacement in 1 hour is

$\displaystyle \vec{x_2}=\vec{v_2}.t_2=.(1)$

$\displaystyle \vec{x_2}=km$

The total displacement is the vector sum of both

$\displaystyle \vec{x_t}=\vec{x_1}+\vec{x_2}=+$

$\displaystyle \vec{x_t}=km$

$\displaystyle \vec{x_t}=$

The distance from the airport is the module of the displacement:

$\displaystyle |\vec{x_t}|=\sqrt{(-746.41)^2+492.82^2}$

$\displaystyle |\vec{x_t}|=894.43\ km$

8 0

3 years ago