For this case, the first thing we must do is define variables.
We have then:
x: altitude of the plane in feet
y: final temperature
The equation modeling the problem for this case is given by:
Thus, evaluating the function for x = 11,000 ft. Height we have:
Answer:
the temperature at an altitude of 11,000 ft is 47.6 F
Answer:
it is 625
Step-by-step explanation:
Answer:
Similar, AA similarity, ΔAKL
Step-by-step explanation:
BC and KL are parallel. Therefore, ∠B and ∠K are alternate interior angles, and ∠C and ∠L are also alternate interior angles. Alternate interior angle are congruent, so by AA similarity, ΔABC ~ ΔAKL.
F(x) = 3x + 1.....this is the same as y = 3x + 1.
In y = mx + b form, which is what y = 3x + 1 is in, the rate of change (slope) is in the m position and the y int (the initial value) is in the b position.
y = mx + b
y = 3x + 1
ur rate of change (slope)...number in the m position = 3
ur initial value (y int)...number in the b position = 1
so rate of change = 3 and initial value = 1
In the given term 
the degree is 3
Step-by-step explanation:
We need to find the degree of the term
The degree of the term is equal to the highest power of the non-zero co-efficient
So, in the given term the degree is 3
Keywords: Degree of terms
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