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velikii [3]
2 years ago
15

Can someone help with these geometry questions? I gotta have answers fast, it’s urgent:(

Mathematics
1 answer:
Eduardwww [97]2 years ago
7 0

Can't answer 1-6 cause I have no idea what you need

7) A triangle with two congruent sides is isosceles.

8) \overline{AC} and \overline{BC}

9) \angle C

10) \overline{AB}

11) \angle A, \angle B

12) isosceles triangle

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Please help me! What is the length of EF in the right triangle below?
scoray [572]
Use the pythagorean theorem:
EF² +DF²=DE²
EF²=18²-12²=180
EF=√180
E is the answer. 
4 0
4 years ago
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What is the value of 106 ?
Artemon [7]
Is that meant to be 10 to the power of 6?
Assuming it is it would be 10×10×10×10×10×10.
This equals 1,000,000 so the answer is C.
7 0
4 years ago
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A 75% increase followed by a 33 1/2% decrease​
o-na [289]

After 75% increase followed by a 33 1/2% decrease the net increased is 16.375%.

<u>Solution:</u>

Need to determine net percentage increase or decrease when a value is increased by 75% and then decreased by 33 \frac{1}{2} \% that is 33.5%.

Let’s assume initial value be represented by variable x.

75 \% \text { decrease means } x+75 \% \text { of } x=x+\frac{75}{100} x=x+0.75 x=1.75 x

Now there is decrease of 33.5%

\begin{array}{l}{33.5 \% \text { decrease means } 1.75 x-33.5 \% \text { of } 1.75 x=1.75 x-\frac{33.5}{100} \times 1.75 x} \\\\ {=1.75 x-(0.335 \times 1.75) x=1.75 x-0.58625 x} \\\\ {=1.16375 x}\end{array}

\text { So increase in percentage }=\frac{\text { final value-initial value}}{\text { intial value }}

=\frac{1.16375 x-x}{x} \times 100=16.375 \%

Hence after 75% increase followed by a 33 \frac{1}{2} \% decrease the net increased is 16.375%.

8 0
3 years ago
What is the input value for the following function if the output value is 1.2?<br><br> y = x - 0.4
Advocard [28]
So it would be 1.2=X-0.4 and solve to get your answer. Output means the y-intercepts.
8 0
3 years ago
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Find the length of the missing side of the right triangle.​
Vladimir79 [104]
Here you are trying to find the hypotenuse. So you would take
5^2 (five squared) plus 12^2 (twelve squared) and add them using the equation a^2+b^2= c^2. Now you square 5 and 12 to get 25 and 144. You add them together and get 169. Take the square root of 169 and c. The square root on c will cancel out the squared (to the power of two) part leaving you with just c. And the square root of 169 is 13. So c (the missing length) is 13. C=13.
4 0
4 years ago
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