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vekshin1
3 years ago
8

The running tracks of two different playgrounds are shown below. Figure A is a semicircle with a diameter of 100 m. Figure B is

composed of two semicircles and a square with sides of 100 m. How much farther would an athlete run if they ran around the track in Figure B vs. the track in Figure A?

Mathematics
2 answers:
irga5000 [103]3 years ago
7 0
Figure A only answer 650 because perimeter of a semi circle is 1/2multiplied by pie which is 22/7multiplied by 100+100 because perimeter is all round and you will find your answer as650m
crimeas [40]3 years ago
4 0

Answer:

10157.08 m

Step-by-step explanation:

Find the area of the square, and get 10000, from multiplying 100 by 100. Then, find the circumference/area of the semi-circle as a whole circle. 314.16m. Divide it by 2 and get 157.08 m. Add everything up and get 10157.08 m. Remember, that we aren't calculating the total of both semi-circles because we subtract Figure A from Figure B.

Note:

Pls, notify me if my answer is correct, for the other users that will see this message.

<em>-kiniwih426</em>

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EXPLANATION

Given information

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To find the length of the rectangular field, follow the steps below

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\begin{gathered} \text{ The perimeter of a rectangular field = 2\lparen l + w\rparen} \\ \text{ where l =length, and w = width} \end{gathered}

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\begin{gathered} \text{ Perimeter = 2 \lparen l + w\rparen} \\ \text{ Perimeter = 372 yards} \\ \text{ width = 87 yards} \\ \text{  372 = 2\lparen l + 87\rparen} \\ \text{ Divide both sides by 2} \\ \text{ }\frac{372}{2}\text{ = }\frac{2}{2}(l\text{ + 87\rparen} \\ 186\text{ = l + 87} \\ \text{  subtract 87 from each sides of the equation} \\ \text{ 186 - 87 = l + 87 - 87} \\ \text{  99 = l} \\ l\text{ = 99 yards} \end{gathered}

Hence, the length of the rectangular field is 99 yards

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