All categories

3 years ago

Help me! I'm the most stupidest person ever!

Mathematics

2 answers:

vovangra [49]3 years ago

6 0

Alright here's the breakdown:
your trying to find how many miles per day
so
take the miles (290) and the days it took (5)
and
divide the miles by the days it took (290/5)
and the answer is
58 mi. per day

Natalija [7]3 years ago

3 0

No the answer is 1,450 like for real ask Siri or something

You might be interested in

A rectangular box has length 20cm, width 6cm and height 4cm. find how many cubes of size 2cm that will fit into the box.

Papessa [141]

Answer:

$\boxed{\pink{\sf The \ number \ of \ cubes \ that \ can \ be \ fitted \ is 60 .}}$

Step-by-step explanation:

Given dimensions of the box = 20cm × 6cm × 4cm .

Dimension of the cube = 2cm × 2cm × 2cm .

Therefore the number of cubes that can be fitted into the box will be equal to the Volume of box divided by the Volume of the cube. So ,

$\boxed{\red{\bf \implies No. \ of \ cubes \ = \dfrac{Volume \ of \ box}{Volume \ of \ cube }}}$

$\bf \implies n_{cubes} = \dfrac{20cm \times 6cm \times 4cm .}{2cm \times 2cm \times 2cm } \\\\\bf\implies n_{cubes} = 10 \ times 3cm \times 2cm \\\\\implies \boxed{\bf n_{cubes}= 60 }$

<h3>Hence the number of cubes that can be fitted in the box is 60 .</h3>

6 0

3 years ago

How many square inches are 9 cubes with a 1 inch edge

ki77a [65]

Add it up then you will get answer

4 0

3 years ago

Find the slope when given the following points (1 6) and (3 -4)

aalyn [17]

Answer:

Slope= (-4-6)/(3-1)

=-10/2

=-5

7 0

3 years ago

What three things must a ordered pair have?

igor_vitrenko [27]

Answer: An x and y value, parenthesis around the values, and a comma in between them.

Examples of ordered pairs: (2, 5), (1872, 1683), (-3, 7), (7/8, -10/2)

3 0

3 years ago

Evaluate the integral. 3 2 t3i t t − 2 j t sin(πt)k dt

sveta [45]

∫(t = 2 to 3) t^3 dt

= (1/4)t^4 {for t = 2 to 3}

= 65/4.

----

∫(t = 2 to 3) t √(t - 2) dt

= ∫(u = 0 to 1) (u + 2) √u du, letting u = t - 2

= ∫(u = 0 to 1) (u^(3/2) + 2u^(1/2)) du

= [(2/5) u^(5/2) + (4/3) u^(3/2)] {for u = 0 to 1}

= 26/15.

----

For the k-entry, use integration by parts with

u = t, dv = sin(πt) dt

du = 1 dt, v = (-1/π) cos(πt).

So, ∫(t = 2 to 3) t sin(πt) dt

= (-1/π) t cos(πt) {for t = 2 to 3} - ∫(t = 2 to 3) (-1/π) cos(πt) dt

= (-1/π) (3 * -1 - 2 * 1) + [(1/π^2) sin(πt) {for t = 2 to 3}]

= 5/π + 0

= 5/π.

Therefore,

∫(t = 2 to 3) <t^3, t√(t - 2), t sin(πt)> dt = <65/4, 26/15, 5/π>.

3 0

3 years ago