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nekit [7.7K]
3 years ago
14

Please can someone answer the question on the attachment ‼️

Mathematics
1 answer:
Lena [83]3 years ago
4 0

Answer: C

Step-by-step explanation: brainliest

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A certain shade of green paint is made by mixing blue and yellow paint. The relationship between the number of quarts of blue pa
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Answer:

2 quartz of the blue paint for every 10 quartz of yellow paint

Step-by-step explanation:

The graph shows the possible different amount of yellow paint and blue paint, in quartz, that can be mixed to obtain a shade of green paint.

On the graph, at the point with the coordinates pair of (2, 10), it means for we would require 2 quartz of blue paints to be mixed with every 10 quartz of yellow paint in order to get the shade of the green paint that we are looking for.

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3 years ago
PLEASE HELP!!! (Thank you) :)
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The answer is 26 divided by 2 witch is 13
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2 years ago
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The SAT scores have an average of 1200 with a standard deviation of 60. A sample of 36 scores is selected. a) What is the probab
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Answer:

a) 0.0082

b) 0.9987

c) 0.9192

d) 0.5000

e) 1

Step-by-step explanation:

The question is concerned with the mean of a sample.  

From the central limit theorem we have the formula:

z=\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }

a) z=\frac{1224-1200}{\frac{60}{\sqrt{36} } }=2.40

The area to the left of z=2.40 is 0.9918

The area to the right of z=2.40 is 1-0.9918=0.0082

\therefore P(\bar X\:>\:1224)=0.0082

b) z=\frac{1230-1200}{\frac{60}{\sqrt{36} } }=3.00

The area to the left of z=3.00 is 0.9987

\therefore P(\bar X\:

c) The z-value of 1200 is 0

The area to the left of 0 is 0.5

z=\frac{1214-1200}{\frac{60}{\sqrt{36} } }=1.40

The area to the left of z=1.40 is 0.9192

The probability that the sample mean is between 1200 and 1214 is

P(1200\:

d) From c) the probability that the sample mean will be greater than 1200 is 1-0.5000=0.5000

e) z=\frac{73.46-1200}{\frac{60}{\sqrt{36} } }=-112.65

The area to the left of z=-112.65 is 0.

The area to the right of z=-112.65 is 1-0=1

5 0
3 years ago
Assume that females have pulse rates that are normally distributed with a mean of u = 75.0 beats per minute and a standard devia
Elan Coil [88]

Answer:

36.88% probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 75, \sigma = 12.5

Find the probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

This is the pvalue of Z when X = 81 subtracted by the pvalue of Z when X = 69.

X = 81

Z = \frac{X - \mu}{\sigma}

Z = \frac{81 - 75}{12.5}

Z = 0.48

Z = 0.48 has a pvalue of 0.6844

X = 69

Z = \frac{X - \mu}{\sigma}

Z = \frac{69 - 75}{12.5}

Z = -0.48

Z = -0.48 has a pvalue of 0.3156

0.6844 - 0.3156 = 0.3688

36.88% probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

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