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Tamiku [17]
3 years ago
12

Please help! !!!!!!!!!!!!!!

Mathematics
1 answer:
kirill [66]3 years ago
5 0

its y=3/4x + 2 because your slope (rise/run) is 3 up and 4 across and the plus 2 is the y intercept witch is 2. I hope this helps you

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Find the value of R so that the line that passes through each pair of points has the given slope: (8, -2 ), (r, -6), m=-4
kondor19780726 [428]
\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 8}}\quad ,&{{ -2}})\quad 
%   (c,d)
&({{ r}}\quad ,&{{ -6}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-6-(-2)}{r-8}=-4
\\\\\\
\cfrac{-6+2}{r-8}=-4\implies -4=-4(r-8)\implies \cfrac{-4}{-4}=r-8\\\\\\ 1+8=r
8 0
3 years ago
(1 ÷ x- 1)+(2÷ x+2)=(3÷2) solve and check for extraneous solutions
Sliva [168]
\frac{1}{x-1}+ \frac{2}{x+2}= \frac{3}{2}
\frac{1(x+2)}{(x-1)(x+2)}+ \frac{2(x-1)}{(x+2)(x-1)}= \frac{3(x-1)(x+2)}{2}
\frac{x+2+2(x-1)}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}
\frac{x+2+2x-1}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}
\frac{3x+1}{(x-1)(x+2)}= \frac{3(x^2+x-2)}{2}
\frac{}{(x-1)(x+2)}= \frac{3x^2+3x-6)}{2}
\frac{3x+1}{(x^2+x-2)}= \frac{3x^2+3x-6)}{2}
\frac{2(3x+1)}{2(x^2+x-2)}= \frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}
\frac{2(3x+1)}{2(x^2+x-2)}-\frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}=0
\frac{2(3x+1)-3x^2+3x-6}{2(x^2+x-2)}=0

this will be continued
5 0
4 years ago
What is the area of Triangle PQR on the grid?
kupik [55]

Answer:

4 units

Step-by-step explanation:

You have a triangle. This means that the formula is 1/2 x b x h. So its 2 x 4 = 8. Then its 8 x 1/2 which gives you 4.

6 0
3 years ago
Read 2 more answers
Please help me! I will mark you brainliest!
AleksAgata [21]

Answer:

1

Step-by-step explanation:

8 0
3 years ago
(x+1)^1/2
Step2247 [10]

Answer:

Step-by-step explanation:

L.C.M. of 2 and 3=6

Raise to the power 6

8 0
3 years ago
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