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Marta_Voda [28]

3 years ago

12

How do you find the 50th derivative of y=cos(x)y=cos(x) ?

1 answer:

Vadim26 [7]3 years ago

5 0

$y=cosx\\\\y'=-sinx\\\\y''=-cosx\\\\y'''=-(-sinx)=sinx\\\\y''''=cosx\to again\ this\ same...\\\\50:4=12+(R=2)\\\\50th\ derivate\ of\ y=cosx\ is\ equal\ y''=-cosx$

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ANSWER ALL THE QUESTIONS IN THIS WORKBOOK.

777dan777 [17]

Answer:

i. 15, 18, 20, 20, 25

ii.

a) 19.6

b) 20

c) 20

d) 10

Step-by-step explanation:

8 0

2 years ago

Need help asap ..! please and thank you

Hunter-Best [27]

The slope of the line is positive

7 0

3 years ago

What is the result of adding these two equations? \begin{aligned} 2x+3y &= -5 \\\\ 5x-y &= -12 \end{aligned} 2x+3y 5x−y

EleoNora [17]

Answer:

$7x+2y = -17$

Step-by-step explanation:

We have the following equations:

$2x+3y = -5$

$5x-y = -12$

If we want to add these equations, we just need to add x-terms, y-terms and independent terms.

$(2x+5x)+(3y-y) = -5-12$

$7x+2y = -17$

I hope it helps you!

7 0

2 years ago

The manager of a music store has kept records of

Marysya12 [62]

Answer:

(a) $P(x\le 3) = 0.75$

(b) $P(x\le 3) = 0.75$

<em>(b) is the same as (a)</em>

(c) $P(x \ge 5) = 0.10$

(d) $P(x = 1\ or\ 2) = 0.55$

(e) $P(x > 2) = 0.45$

Step-by-step explanation:

Given

$\begin{array}{ccccccc}{CDs} & {1} & {2} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.30} & {0.25} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}$

Solving (a): Probability of 3 or fewer CDs

Here, we consider:

$\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}$

This probability is calculated as:

$P(x\le 3) = P(1) + P(2) + P(3)$

This gives:

$P(x\le 3) = 0.30 + 0.25 + 0.20$

$P(x\le 3) = 0.75$

Solving (b): Probability of at most 3 CDs

Here, we consider:

$\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}$

This probability is calculated as:

$P(x\le 3) = P(1) + P(2) + P(3)$

This gives:

$P(x\le 3) = 0.30 + 0.25 + 0.20$

$P(x\le 3) = 0.75$

<em>(b) is the same as (a)</em>

<em />

Solving (c): Probability of 5 or more CDs

Here, we consider:

$\begin{array}{ccc}{CDs} & {5} & {6\ or\ more}\ \\ {Prob} & {0.05} & {0.05}\ \ \end{array}$

This probability is calculated as:

$P(x \ge 5) = P(5) + P(6\ or\ more)$

This gives:

$P(x\ge 5) = 0.05 + 0.05$

$P(x \ge 5) = 0.10$

Solving (d): Probability of 1 or 2 CDs

Here, we consider:

$\begin{array}{ccc}{CDs} & {1} & {2} \ \\ {Prob} & {0.30} & {0.25} \ \ \end{array}$

This probability is calculated as:

$P(x = 1\ or\ 2) = P(1) + P(2)$

This gives:

$P(x = 1\ or\ 2) = 0.30 + 0.25$

$P(x = 1\ or\ 2) = 0.55$

Solving (e): Probability of more than 2 CDs

Here, we consider:

$\begin{array}{ccccc}{CDs} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}$

This probability is calculated as:

$P(x > 2) = P(3) + P(4) + P(5) + P(6\ or\ more)$

This gives:

$P(x > 2) = 0.20+ 0.15 + 0.05 + 0.05$

$P(x > 2) = 0.45$

3 0

3 years ago

Simplifiy the given epression<br> (-3.2)^0

siniylev [52]

Answer:

(-3.2)^0 = 1

Step-by-step explanation:

Anything to the power of 0 equals 1.

6 0

3 years ago

Read 2 more answers