6nsquared - 5nsquared + 7nsquared simplify the expression

2 answers:

5 0

6n^2-5n^2= n^2

n^2+7n^2= 8n^2

Final answer: 8n^2
Remember that all of these terms are like terms so you can just add/subtract coefficients.

Vitek1552 [10]3 years ago

5 0

The equation is 6n^2-5n^2+7n^2. Since the exponents are the same, you can just add and subtract. 6n^2-5n^2=n^2. N^2+7n^2=8n^2. The answer to this is 8n^2. I hope this helps! :)

You might be interested in

For what value n is 1P3 =nP4?

Serggg [28]

Answer:

I don't know if this helps, just a picture not a link

3 0

3 years ago

What is the solution to the compound inequality in interval notation?

Eduardwww [97]

First solve the 2 inequalities for x:-

x > 0 or x <= -5

The last choice is the correct one.

5 0

3 years ago

Read 2 more answers

The mayor is interested in finding a 98% confidence interval for the mean number of pounds of trash per person per week that is

saul85 [17]

Solution :

Given :

Sample mean, $\overline X = 34.2$

Sample size, n = 129

Sample standard deviation, s = 8.2

a. Since the population standard deviation is unknown, therefore, we use the t-distribution.

b. Now for 95% confidence level,

α = 0.05, α/2 = 0.025

From the t tables, T.INV.2T(α, degree of freedom), we find the t value as

t =T.INV.2T(0.05, 128) = 2.34

Taking the positive value of t, we get

Confidence interval is ,

$\overline X \pm t \times \frac{s}{\sqrt n}$

$34.2 \pm 2.34 \times \frac{8.2}{\sqrt {129}}$

(32.52, 35.8)

95% confidence interval is (32.52, 35.8)

So with $95 \%$ confidence of the population of the mean number of the pounds per person per week is between 32.52 pounds and 35.8 pounds.

c. About $95 \%$ of confidence intervals which contains the true population of mean number of the pounds of the trash that is generated per person per week and about $5 \%$ that doe not contain the true population of mean number of the pounds of trashes generated by per person per week.