Solve each equation -10=-14v+14v

Mathematics

1 answer:

Vinvika [58]3 years ago

3 0

Answer:

No solution.

Step-by-step explanation:

Simplify. Combine like terms:

-10 = -14v + 14v

-10 = (-14v + 14v)

-10 = (0)

-10 ≠ 0 ∴ no solution is your answer.

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Find the prime factorizations foor the following numbers 36 and 84

Varvara68 [4.7K]

Answer:

36 = 2² * 3²
84 = 2² * 3 * 7

Explanation:

Pf of 36 = 2 * 2 * 3 * 3 which then becomes 2 (to the power of 2) times 3 (to the power of 2)

Pf of 84 = 2 * 2 * 3 * 7 which then becomes 2 (to the power of 2) * 3 * 7

If this helps it would be greatly appreciated if you thanked me.

6 0

4 years ago

If <img src="https://tex.z-dn.net/?f=%20x%20%3D%20%5Cfrac%7B2y%7D%7Ba%7D%20" id="TexFormula1" title=" x = \frac{2y}{a} " alt=" x

inessss [21]

$\bf A) \\\\\\ \cfrac{3\left( \frac{2y}{a} \right)}{y}\implies \cfrac{\frac{6y}{a}}{y}\implies \cfrac{6y}{a}\cdot \cfrac{1}{y}\implies \cfrac{6}{a}\quad \otimes \\\\\\ B) \\\\\\ \cfrac{6\left( \frac{2y}{a} \right)}{y}\implies\cfrac{\frac{12y}{a}}{y}\implies \cfrac{12y}{a}\cdot \cfrac{1}{y}\implies \cfrac{12}{a}\quad \otimes \\\\\\ C) \\\\\\ \cfrac{6y}{\left( \frac{2y}{a} \right)}\implies \cfrac{6y}{1}\cdot \cfrac{a}{2y}\implies 3a\quad \otimes$

$\bf D) \\\\\\ \cfrac{12\left( \frac{2y}{a} \right)}{y}\implies \cfrac{\frac{24y}{a}}{y}\implies \cfrac{24y}{a}\cdot \cfrac{1}{y}\implies \cfrac{24}{a}\quad \otimes \\\\\\ E) \\\\\\ \cfrac{12y}{\left( \frac{2y}{a} \right)}\implies \cfrac{12y}{1}\cdot \cfrac{a}{2y}\implies 6a\quad \checkmark$