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Butoxors [25]
3 years ago
12

Solve each equation -10=-14v+14v

Mathematics
1 answer:
Vinvika [58]3 years ago
3 0

Answer:

No solution.

Step-by-step explanation:

Simplify. Combine like terms:

-10 = -14v + 14v

-10 = (-14v + 14v)

-10 = (0)

-10 ≠ 0 ∴ no solution is your answer.

~

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Graph the equation in a graphing calculator or in the table in a regular calculator and look for the zero on the x axis and the y axis
8 0
4 years ago
Huxian's father gives her $120 as her monthly allowance. a) If she spends an average of 5 dollars a day, find the amount on mone
abruzzese [7]

Answer:

3 days=  $105, 6 days= $90, 10 days= $70

Step-by-step explanation:

You can rewrite this equation as y=120-5x

x is the amount of days passed

plug in 3 for x and you get 15. 120-15=105

plug in 6 for x and you get 30. 120-30=90

plug in 10 for x you get 50. 120-50=70

Hope this helps!

:)

4 0
3 years ago
Solve the system of equation <br> Y=4x-11<br> Y=x+13<br><br> X=<br><br><br> Y =
Phoenix [80]

Answer:

(8,21)

Step-by-step explanation:

Since both equations equal y, set both equaitions equal to each other

and solve for x

4x-11=x+13 , subtract x from both sides

3x-11=13, add eleven to both sides

3x=24, divide both sides by 3 to get x alone

x=8

Substitute x=8 into either equation to solve for y

y=4(8)-11

y=32-11

y=21

5 0
4 years ago
Solve the equation. And write all solutions in general form.
Amiraneli [1.4K]

Answer:

x = pi/2 + 2 pi n                            x = pi + 2 pi n   where n is an integer

x = 5pi /3 + 2 pi n                      

Step-by-step explanation:

8 cos^2 x + 4 cos x-4 = 0

Divide by 4

2 cos^2 x +  cos x-1 = 0

Let u = cos x

2 u^2 +u -1 =0

Factor

(2u -1) ( u+1) = 0

Using the zero product property

2u-1 =0    u+1 =0

u = 1/2      u = -1

Substitute cosx for u

cos x = 1/2    cos x = -1

Take the inverse cos on each side

cos ^-1(cos x) = cos ^-1(1/2)   cos ^-1( cos x) =cos ^-1( -1)

x = pi/2 + 2 pi n                            x = pi + 2 pi n   where n is an integer

x = 5pi /3 + 2 pi n                      

8 0
3 years ago
Lydia graphed ΔDEF at the coordinates D (−2, −1), E (−2, 2), and F (0, 0). She thinks ΔDEF is a right triangle. Is Lydia's asser
alukav5142 [94]

Answer:

No; the slopes of segment EF and segment DF are not opposite reciprocals.

Step-by-step explanation:

The slope between two points O(e, f) and X (g,h) is given as:

slope\ of\ |OX|=\frac{h-f}{g-e}

The slopes of segment EF and segment DF are given below:

slope\ of\ |EF|=\frac{0-2}{0-(-2)}=-1\\\\slope\ of\ |DF|=\frac{0-(-2)}{0-(-1)}=2\\

For triangle DEF to be a right triangle, DF and EF are supposed to be perpendicular to each other. Two line are said to be perpendicular if the product of their slope is -1, i.e the slope of one line is the negative reciprocal (opposite reciprocal) of the other line.

Since the slope of DF and EF are not opposite reciprocals,  ΔDEF is not a right triangle.

3 0
3 years ago
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