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notsponge [240]
3 years ago
11

What is the unit rate of 88 students for 4 classes

Mathematics
1 answer:
Nat2105 [25]3 years ago
5 0
So, We Have A Rate That We Need To Simplify. We Have:
88 students for every 4 classes
So, We Need To Simplify This Rate. In Order To Do This, We Need To Change Is To A Fraction. It Is:
88 students
---------------
  4 classes

Now, We Have To Simplify. We Can Do That By Remembering How To Simplify Fractions.

So,
88 ÷ 2 =  44   ÷ 2  =   22 students
---            ---               ---------------
 4  ÷ 2 =   2    ÷ 2  =           1

So, The Unit Rate For 88 Students For 4 Classes Is:
22 Students For One Class

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Two less than 3/2 of a number (x) is more than 5 1/2
garik1379 [7]

Answer:

3/2x-2>5 1/2

Step-by-step explanation:

Two less than a number means we are subtracting 2, so we can write it into the equation as -2.

Since we dont know the value of x, we can just write 3/2 of x by multiplying 3/2 by x. So 3/2x. Also, since we are subtracting two from 3/2x, -2 comes after 3/2x.

Now, since it says that it is more than 5 1/2, we could use the greater than sign (>), to express that. So >5  1/2

Our final expression is 3/2x-2>5 1/2.

Hope this helps!

3 0
3 years ago
What is the value of x? Enter your answer in the box. mm Triangle V T K with segment T Y such that Y is on segment V K, between
lapo4ka [179]

Answer:

  VK = x = 98 mm

Step-by-step explanation:

TY is the bisector of angle T, so it divides segments of the triangle proportionally. That is, ...

  VY/VT = KY/KT

  VY = VT·KY/KT = (57 mm)·68/192.2 = 30 mm

Then

  VK = VY + YK = 30 mm + 68 mm

  VK = 98 mm

5 0
3 years ago
Read 2 more answers
Evaluate this expression.
Colt1911 [192]

Answer:

-115.62

Step-by-step explanation:

bhjka,f

5 0
3 years ago
Kenny mowed a lawn today to earn some extra money. He spent $1.40 on fuel and $3.25 on lunch. He charged $15 to mow the lawn.
mrs_skeptik [129]
His profit from mowing the lawn was 10.35
7 0
3 years ago
How to solve the problem
USPshnik [31]
X = 0, y = 4, z = -3

You can solve this by using the two equations with the z to create a fourth equation. Get the z's to equal each other my multiplying the whole equation by factors that would do so. Then subtract them from each other to get it to cancel out. Then you can use that equation along with the middle equation to solve for either x or y in the same way. Once you have one answer, you can use the middle equation to find the second one and any equation to find z. 
6 0
3 years ago
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