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notsponge [240]
4 years ago
11

What is the unit rate of 88 students for 4 classes

Mathematics
1 answer:
Nat2105 [25]4 years ago
5 0
So, We Have A Rate That We Need To Simplify. We Have:
88 students for every 4 classes
So, We Need To Simplify This Rate. In Order To Do This, We Need To Change Is To A Fraction. It Is:
88 students
---------------
  4 classes

Now, We Have To Simplify. We Can Do That By Remembering How To Simplify Fractions.

So,
88 ÷ 2 =  44   ÷ 2  =   22 students
---            ---               ---------------
 4  ÷ 2 =   2    ÷ 2  =           1

So, The Unit Rate For 88 Students For 4 Classes Is:
22 Students For One Class

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Help !? Pls, don’t understand math that much
Arlecino [84]
Day 1: $2.70 is added to the value of the share. 
           $43.85 + $2.70 = $46.55 

Day 2: $2.70 is added to the value of the share. 
           $46.55 + $2.70 = $49.25

Day 3: $1.10 is subtracted from the value of the share. 
           $49.25 - $1.10 = $48.15 

Day 4: $1.10 is subtracted from the value of the share. 
           $48.15 - $1.10 = $47.05 

Day 5: $4.45 is subtracted from the value of the share. 
           $47.05 - $4.45 = $42.60 

After 5 days, the value is $42.60, which is choice B. 
Hope this helps!
5 0
3 years ago
Line segment GT contains the point G(−3, 5) and a midpoint at A(1, −4). What is the location of endpoint T?
algol [13]

Imagine you're moving along the segment. Since the midpoint is in the middle of the segment (obviously), it means that when you've traveled from G to A, you're halfway through your journey, along both x and y directions. So, let's break the problem in two and analyze both directions.


Along the x axis, you've moved from -3 to 1, so you moved 4 units forward. This means that you have 4 units still to go, and your journey will end at coordinate 5.


Similarly, along the y axis, you've moved from 5 to -4, so you moved 9 units downward. This means that you have 9 units still to go, and your journey will end at coordinate -13.


So, the coordinates of the endpoint are T = (5,-13)


If you prefer a more analyitical approach, simply write the definition of the midpoint and solve it for the coordinates of T.


We have G = (-3, 5) and T = (x_T,y_T). The midpoint is computed as


A = \left( \frac{-3+x_T}{2},\frac{5+y_T}{2} \right) = (1, -4)


So, you have the equations


\frac{-3+x_T}{2} = 1,\qquad \frac{5+y_T}{2} = -4


Multply both equations by 2 to get


-3+x_T = 2,\qquad 5+y_T = -8


Move the constants to the right hand sides to get


x_T = 5,\qquad y_T = -13

8 0
3 years ago
I RLLY NEED HELP FAST!!!!!!!!!!!!!!!
rodikova [14]
Hello!

You look at where J is 2 and look at where the line is for K

At J = 2, K = 20

The answer is 20

Hope this helps!
7 0
4 years ago
Simplify the following expression. 3^11/5 divided by 3^-9/5
san4es73 [151]

Answer:

Answer is 81.

Step-by-step explanation:

Given two expressions are 3^{\frac{11}{5} } and 3^{-\frac{9}{5} }

Now we divide first expression by the second.

\frac{3^{\frac{11}{5} }}{3^{-\frac{9}{5} } }

3^{\frac{11}{5} }.3^{\frac{9}{5} }

3^{\frac{11}{5}+\frac{9}{5}} = 3^{\frac{20}{5} }=3^{4}=81

Therefore 81 is the answer.

6 0
3 years ago
Read 2 more answers
Compare the value of the following expression with zero. 5a^3b^2/a+b, where a<0, b<0
ira [324]

Answer:

The given expression will be greater than zero.

Step-by-step explanation:

If a < 0 and b < 0, then 5a^3 is < 0 (5a^3) is negative;

but b^2 is > 0.

Then (5a^3)*(b^2) < 0

and if we divide this quantity by a + b (which is negative), the end result will be > 0.

3 0
3 years ago
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