I hope this helps you
-8x+2. (4x+6)@=12
-8x+8x+12=12
12=12
0=0
Lets factor first to see if we can make the problem simple
2(4x^2-25)
now we see that in parenthesis we have 2 square numbers
4x^2=(2x)^2
25=(5)^2
our expression is now
2(2x+5)(2x-5)
Answer:
-15
Step-by-step explanation:
-3+-2*5-2=-15
Answer:
Hey there!
We can solve this by multiplying 0.3 by 546, which is about 164.
Hope this helps :)
Answer:
The values of 
so that 
have vertical asymptotes are 
, 
, 
, 
, 
.
Step-by-step explanation:
The function cosecant is the reciprocal of the function sine and vertical asymptotes are located at values of so that function cosecant becomes undefined, that is, when function sine is zero, whose periodicity is . Then, the vertical asymptotes associated with function cosecant are located in the values of of the form:
, 
In other words, the values of so that have vertical asymptotes are , , , , .
