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Bogdan [553]
3 years ago
9

An aluminum can has a radius of 1 inch and a height of 5 inches. In terms of π , what is the volume of the can?

Mathematics
1 answer:
Katen [24]3 years ago
7 0

Answer:

The answer to your question is 5π in³

Step-by-step explanation:

Data

radius = 1 in

height = 5 in

π = π

Process

1.- Write the formula to calculate the volume of a cylinder

     Volume = π x radius² x height

2.- Substitution

     Volume = π x (1)² x (5)

3.- Simplification

     Volume = π x 1 x 5

4.- Result

     Volume = 5π in³

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boyakko [2]
C, 80-75=5 and 95-90=5. Meaning your answer would be 5!
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-45 - 9n = -81

-9n = -81 + 45

-9n = -36

n = -36/-9

n = 4

Hope this helps you. :)

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spayn [35]
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Find f.<br><br> A) 7.4<br><br> B) 8.2<br><br> C) 10.5<br><br> D) 11.1
tatyana61 [14]
F=72

g=6

------------

\cos { \left( F \right)  } =\frac { { e }^{ 2 }+{ g }^{ 2 }-{ f }^{ 2 } }{ 2eg }

Therefore:

\cos { \left( 72 \right)  } =\frac { { e }^{ 2 }+{ 6 }^{ 2 }-{ f }^{ 2 } }{ 2\cdot e\cdot 6 } \\ \\ \cos { \left( 72 \right)  } =\frac { { e }^{ 2 }+36-{ f }^{ 2 } }{ 12e }

\\ \\ 12e\cdot \cos { \left( 72 \right)  } ={ e }^{ 2 }+36-{ f }^{ 2 }\\ \\ \therefore \quad { f }^{ 2 }={ e }^{ 2 }-12e\cdot \cos { \left( 72 \right)  } +36\\ \\ \therefore \quad f=\sqrt { { e }^{ 2 }-12e\cdot \cos { \left( 72 \right) +36 }  } \\ \\ \therefore \quad f=\sqrt { e\left( e-12\cos { \left( 72 \right)  }  \right) +36 }

But what is e?

E=76

G=32

g=6

And:

\frac { e }{ \sin { \left( E \right)  }  } =\frac { g }{ \sin { \left( G \right)  }  }

Which means that:

\frac { e }{ \sin { \left( 76 \right)  }  } =\frac { 6 }{ \sin { \left( 32 \right)  }  } \\ \\ \therefore \quad e=\frac { 6\cdot \sin { \left( 76 \right)  }  }{ \sin { \left( 32 \right)  }  }

If you take this value into account, you will discover that f is...

f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right)  }  }{ \sin { \left( 32 \right)  }  } \left( \frac { 6\cdot \sin { \left( 76 \right)  }  }{ \sin { \left( 32 \right)  }  } -12\cos { \left( 72 \right)  }  \right) +36 } \\ \\ \therefore \quad f=10.8\quad \left( 1\quad d.p \right)

So I would have to say that the answer is approximately (c).
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