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natulia [17]
3 years ago
12

Does anyone know how to solve this?

Mathematics
1 answer:
erik [133]3 years ago
8 0

Answer:

A point in polar coordinates is written as (R, θ)

If we want to transform this point to rectangular coordinates, we get:

x = R*cos(θ)

y = R*sin(θ)

Now we can remember that the sine and cosine functions have a period of 2*pi, then:

cos(θ) = cos(θ + 2*pi)

or:

cos(θ) = cos(θ + 2*pi + 2*pi)

and so on.

Then the point (R, θ) is the same as (R, θ + 2*pi) and (R, θ + k*(2*pi))

where k can be any integer number.

Then if we have a point in polar coordinates:

(-4, -5*π/3)

Then another two polar representations of this point are:

(-4, -5*π/3 + 2*π) = (-4, -5*π/3 + 6*π/3) = (-4, π/3)

Now we can not add 2*π (nor subtract) because we would have an angle outside the range [-2*π, 2*π]

For example, if we have:

(-4, π/3 + 2*π) = (-4, 7*π/3)

And we can not change the value of the radius and get the coordinates for the same point.

So another representation could be something like:

(-8/2, π/3)

Where i just wrote -4 in another way.

Now, a really important point.

When working with polar coordinates, we always use R as a positive number (here you can see that R is negative) so this is not the standard notation for the polar representation of a point.

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A two-factor between-subjects design is evaluated. The F-value for Factor A has df = 1, 40 and the F-value for Factor B has df =
finlep [7]

Answer:

The df values for the A x B interaction are also 3,40

Step-by-step explanation:

The F-value for Factor A has df = 1, 40

The F-value for Factor B has df = 3, 40.

The df values for the A x B interaction are also 3,40

This is because the source of variation between columns has ( c- 1); rc(n-1) degrees of freedom and  the source of variation between  rows has (r-1); rc(n-1) degrees of freedom and the  source of variation of interaction

(between rows and columns)  has ( c-1) ( r-1); rc(n-1) degrees of freedom.

Therefore

Factor A:  ( c- 1); rc(n-1)    = 1,40

<u>Factor B:    (r-1); rc(n-1)     = 3,40</u>

Interaction : ( c-1) ( r-1); rc(n-1)   =  3*1,(40)= 3,40

where c refers to columns , r refers to rows and n refers to the total sample size.

5 0
3 years ago
YOU can answer with A. B. C. or D.​
klemol [59]

Answer: 0.0066248

Step-by-step explanation:

7.28⋅10−2)⋅(9.1⋅10−2)

7.28⋅9.1⋅10−4

66.248⋅10-4

0.0066248

is this wht the question say? If so I hope I help

3 0
3 years ago
Read 2 more answers
Please help me with 9 I really need it
MissTica

Answer:

605 boys

Step-by-step explanation:

If the ratio of boys to girls is 5:7

and there are 847 girls

we can plug this value into the ratio by doing something like:

5:7

= 5/7

= x/847

Because the ratio has to be the same, we can substitute x for the number of boys and solve by the cross method or whatever you guys call it.

5            x

---   x    ------

7          847

The x in the middle is just to show the direction you are multiplying.

the 5 is multiplied by the 847 and the 7 is multiplied by x.

847 * 5 = 4,235

4,235  divided by 7 is 605

605 is your answer.

The cross method can be used in most situations.

* is used to represent multiplication btw

4 0
3 years ago
Help me please (look the picture)
umka2103 [35]
You add 1 to the numerator each time
4 0
3 years ago
A parabola can be drawn given a focus of (5, -3) and a directrix of y=1. Write the equation of the parabola in any form.
Anna71 [15]

Answer:

(x²-10x+33)/(-8) = y

Step-by-step explanation:

The distance between any point on a parabola from both its focus and directrix are the same.

Let's say we have a point (x,y) on the parabola. We can then say that using the distance formula,

\sqrt{(x-5)^2+(y-(-3))^2}is the distance between (x,y) and the focus. Similarly, the distance between (x,y) and the directrix is |y-1| (I use absolute value here because distance is always positive). We can find this equation by taking the shortest distance from the point to the line. Because the closest point to the line will be the same x value as the point itself, the distance is simply the distance between the y value of the point and the y value of the directrix.

Equating the two equations given, we have

\sqrt{(x-5)^2+(y-(-3))^2} = |y-1|

square both sides to get

(x-5)²+(y+3)²=(y-1)²

expand the y components

(x-5)² + y²+6y+9 = y²-2y+1

subtract y²+6y+9 from both sides

(x-5)² = -8y - 8

expand the x components

x²-10x+25 = -8y - 8

add 8 to both sides to isolate the -8y

x²-10x+33 = -8y

divide both sides by -8 to isolate y

(x²-10x+33)/(-8) = y

6 0
3 years ago
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