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3 years ago

Could someone please help? Find the perimeter of each figure.

Mathematics

1 answer:

nydimaria [60]3 years ago

6 0

Answer:

3.6

Step-by-step explanation:

stupid idiot you add them up together go back to 4th grade

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What is n/8=11/5 solve for n<br><br><br> #youngboy comment

mihalych1998 [28]

n should be 8 according to mathmatical laws

8 0

2 years ago

Let y′′′−9y′′+20y′=0. find all values of r such that y=erx satisfies the differential equation. if there is more than one correc

DerKrebs [107]

we are given

differential equation as

$y'''-9y''+20y'=0$

we are given

$y=e^{rx}$

Firstly, we will find y' , y'' and y'''

those are first , second and third derivative

First derivative is

$y'=re^{rx}$

Second derivative is

$y''=r*re^{rx}$

$y''=r^2e^{rx}$

Third derivative is

$y'''=r^2*re^{rx}$

$y'''=r^3e^{rx}$

now, we can plug these values into differential equation

and we get

$r^3 e^{rx}-9r^2 e^{rx}+20re^{rx}=0$

now, we can factor out common terms

$e^{rx}(r^3 -9r^2 +20r)=0$

we can move that term on right side

$(r^3 -9r^2 +20r)=0$

now, we can factor out

$r(r^2 -9r +20)=0$

$r(r-5)(r-4)=0$

now, we can set them equal

$r=0$

$r-5=0$

$r=5$

$r-4=0$

$r=4$

so, we will get

$r=0,4,5$ ...............Answer

4 0

3 years ago

lys-0071 [83]

Answer:

The number of quarters Josie has in her collection of 92 coins 28 quarters

Step-by-step explanation:

The given information are

The total number of coins Josie has = 92

Let the number of quarters she has = x

Therefore, 92 = 8 + 3×x

8 + 3×x = 92

3×x = 92 - 8 = 84

3×x = 84

x = 84/3 = 28

x = 28

The number of quarters Josie has in her collection of 92 coins = 28 quarters.

4 0

3 years ago

D. Evaluate each of the following. (5 points)

Harrizon [31]

Problem 1

f(x) = x + 1/x

f(1) = 1 + 1/1

f(1) = 1 + 1

f(1) = 2

Answer: 2

============================================

Problem 2

(f o f)(1) = f( f(1) )

(f o f)(1) = f( 2 )

(f o f)(1) = 2 + 1/2

(f o f)(1) = 4/2 + 1/2

(f o f)(1) = 5/2

Answer: 5/2

============================================

Problem 3

(f o f o f)(1) = f( f(f(1)) )

(f o f o f)(1) = f( (f o f)(1) )

(f o f o f)(1) = f( 5/2 )

(f o f o f)(1) = 5/2 + 1/(5/2)

(f o f o f)(1) = 5/2 + 2/5

(f o f o f)(1) = 25/10 + 4/10

(f o f o f)(1) = 29/10

Answer: 29/10

============================================

Problem 4

(f o f o f o f)(1) = f( f(f(f(1)) )

(f o f o f o f)(1) = f( (f o f o f)(1) )

(f o f o f o f)(1) = f( 29/10 )

(f o f o f o f)(1) = 29/10 + 1/(29/10)

(f o f o f o f)(1) = 29/10 + 10/29

(f o f o f o f)(1) = 841/290 + 100/290

(f o f o f o f)(1) = 941/290

Answer: 941/290

============================================

Problem 5

(f o f o f o f o f)(1) = f( f(f(f(f(1)))) )

(f o f o f o f o f)(1) = f( (f o f o f o f)(1) )

(f o f o f o f o f)(1) = f( 941/290 )

(f o f o f o f o f)(1) = 941/290 + 1/(941/290)

(f o f o f o f o f)(1) = 941/290 + 290/941

(f o f o f o f o f)(1) = 885481/272890 + 84100/272890

(f o f o f o f o f)(1) = 969581/272890

Answer: 969581/272890

4 0

3 years ago

Read 2 more answers

Complete the table thanks in advance

inna [77]

Y = 1/2 x

for x = 0 → y = 1/2 · 0 = 0
for x = 2 → y = 1/2 · 2 = 1

x | 0 | 2 |
y=1/2x| 0 | 1 |

y = x + 3

for x = 0 → y = 0 + 3 = 3
for x = -3 → y = -3 + 3 = 0

x | 0 | 3 |
y=x+3|-3 | 0 |

6 0

3 years ago