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NeX [460]
3 years ago
8

In this geometric sequence, what is the common ratio?

Mathematics
1 answer:
diamong [38]3 years ago
6 0
Hi there! The correct answer is D. -1/2

104 × -1/2 = -52
-52 × -1/2 = 26
26 × -1/2 = -13
...

Each time you multiply the preceding number by -1/2. Therefore the common ratio in this sequence is -1/2
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What is 4 less than 5 by the 3 power equal
oksano4ka [1.4K]

5 by the 3 is 5X5X5 = 125

125-4 = 121

answer = 121

5 0
3 years ago
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Write 2,930,365 in expanded notation
Snowcat [4.5K]

Step-by-step explanation: The place value chart can help us write a number in expanded notation. When we put 2,930,365 into the place value chart, we can recognize that our number is equal to 2 millions + 9 hundred thousands + 3 ten thousands + 0 thousands + 3 hundreds + 6 tens + 5 units.

The place value chart is attached in the image provided.

5 0
3 years ago
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How do the values in Pascal’s triangle connect to the coefficients?
damaskus [11]

Explanation:

Each row in Pascal's triangle is a listing of the values of nCk = n!/(k!(n-k)!) for some fixed n and k in the range 0 to n. nCk is <em>the number of combinations of n things taken k at a time</em>.

If you consider what happens when you multiply out the product (a +b)^n, you can see where the coefficients nCk come from. For example, consider the cube ...

  (a +b)^3 = (a +b)(a +b)(a +b)

The highest-degree "a" term will be a^3, the result of multiplying together the first terms of each of the binomials.

The term a^b will have a coefficient that reflects the sum of all the ways you can get a^b by multiplying different combinations of the terms. Here they are ...

  • (a +_)(a +_)(_ +b) = a·a·b = a^2b
  • (a +_)(_ +b)(a +_) = a·b·a = a^2b
  • (_ +b)(a +_)(a +_) = b·a·a = a^2b

Adding these three products together gives 3a^2b, the second term of the expansion.

For this cubic, the third term of the expansion is the sum of the ways you can get ab^2. It is essentially what is shown above, but with "a" and "b" swapped. Hence, there are 3 combinations, and the total is 3ab^2.

Of course, there is only one way to get b^3.

So the expansion of the cube (a+b)^3 is ...

  (a +b)^3 = a^3 + 3a^2b +3ab^2 +b^3 . . . . . with coefficients 1, 3, 3, 1 matching the 4th row of Pascal's triangle.

__

In short, the values in Pascal's triangle are the values of the number of combinations of n things taken k at a time. The coefficients of a binomial expansion are also the number of combinations of n things taken k at a time. Each term of the expansion of (a+b)^n is of the form (nCk)·a^(n-k)·b^k for k =0 to n.

6 0
3 years ago
What is the value of B?
iragen [17]

2x^2-12xy-32y^2=2(x-8y)(x+By)\qquad|\text{use distributive property}\\\\2x^2-12xy-32y^2=(2x-16y)(x+By)\\\\2x^2-12xy-32y^2=(2x)(x)+(2x)(By)+(-16y)(x)+(-16y)(By)\\\\2x^2-12xy-32y^2=2x^2+2Bxy-16xy-16By^2\\\\2x^2-12xy-32y^2=2x^2+(2B-16)xy+(-16By)

\text{therefore:}\\\\2B-16=-12\ \text{and}\ -16B=-32\\\\2B=4\ \text{and}\ B=2\\\\B=2\ \text{and}\ B=2\qquadCORRECT

<h3>Answer: B = 2</h3>
8 0
3 years ago
Which polynomial is in standard form?
Tamiku [17]

Answer:

D). 5x^7y^2+7x^6y^5-14x^3y^7+51x^2y^9

Step-by-step explanation:

For better clarity let us re write the options

A).2xy^3+3x^3y^4-4x^4y^5+9x^5y^6

B).8x^5-5y^4-2xy^5+x^2y

C).x^3y^2-3x^2y-9x^4y^3+11x

D).5x^7y^2+7x^6y^5-14x^3y^7+51x^2y^9

To express polynomial with mixed variables in standard form, we begin by the highest coefficient of x to the smallest (we place high precedence on the coefficient  x terms)

5 0
3 years ago
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