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Ann [662]
3 years ago
12

The perimeter of a square is 36what is the area of the square?​

Mathematics
1 answer:
zmey [24]3 years ago
6 0

Answer: 81 units²

Step-by-step explanation: To solve this problem, remember that the formula for the area of a square is 4s.

Therefore, since the perimeter of the given square is 36, we have 36 = 4s and dividing both sides by 4, 9 = s.

Now, remember that the formula for the area of a square is s² and since the length of a side of the given square is 9, we have (9)² or 81.

So the area of a square that has a perimeter of 36 is 81 units².

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if an office of 36 typist uses 12 dozen envelopes per day how many dozen envelope would an office of 125 typists of use?
Pani-rosa [81]
Assuming the envelope consumption is proportional to the number of typists, you have ...
  (12 dz)/36 = x/125
  125*(12 dz)/36 = x = 41 2/3

An office of 125 typists would use 41 2/3 dozen envelopes per day.
6 0
3 years ago
Answer<br> (5.2 + 6.3) - 12 ÷ 2.5
sweet [91]

Answer:

-0.2

Step-by-step explanation:

5.2 + 6.3 = 11.5

11.5 - 12 / 2.5

-0.5 / 2.5

= -0.2

5 0
3 years ago
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Can anyone pls help me to solve question 2 f and g and pls provide me a explanation I’m with that questions for three days
zvonat [6]

Answer:

  f)  a[n] = -(-2)^n +2^n

  g)  a[n] = (1/2)((-2)^-n +2^-n)

Step-by-step explanation:

Both of these problems are solved in the same way. The characteristic equation comes from ...

  a[n] -k²·a[n-2] = 0

Using a[n] = r^n, we have ...

  r^n -k²r^(n-2) = 0

  r^(n-2)(r² -k²) = 0

  r² -k² = 0

  r = ±k

  a[n] = p·(-k)^n +q·k^n . . . . . . for some constants p and q

We find p and q from the initial conditions.

__

f) k² = 4, so k = 2.

  a[0] = 0 = p + q

  a[1] = 4 = -2p +2q

Dividing the second equation by 2 and adding the first, we have ...

  2 = 2q

  q = 1

  p = -1

The solution is a[n] = -(-2)^n +2^n.

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g) k² = 1/4, so k = 1/2.

  a[0] = 1 = p + q

  a[1] = 0 = -p/2 +q/2

Multiplying the first equation by 1/2 and adding the second, we get ...

  1/2 = q

  p = 1 -q = 1/2

Using k = 2^-1, we can write the solution as follows.

The solution is a[n] = (1/2)((-2)^-n +2^-n).

 

5 0
2 years ago
ILL GIVE A BRAINLIEST FOR THE ANSWER THAT HELPS ME THE MOSTT.​
Nuetrik [128]
he would be born june 12 1962
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3 years ago
Can someone help me on 13<br><br><br><br> Plz
Ad libitum [116K]
10(3) + 3 = 33 times in 2 minutes
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