Assuming the envelope consumption is proportional to the number of typists, you have ...
(12 dz)/36 = x/125
125*(12 dz)/36 = x = 41 2/3
An office of 125 typists would use 41 2/3 dozen envelopes per day.
Answer:
-0.2
Step-by-step explanation:
5.2 + 6.3 = 11.5
11.5 - 12 / 2.5
-0.5 / 2.5
= -0.2
Answer:
f) a[n] = -(-2)^n +2^n
g) a[n] = (1/2)((-2)^-n +2^-n)
Step-by-step explanation:
Both of these problems are solved in the same way. The characteristic equation comes from ...
a[n] -k²·a[n-2] = 0
Using a[n] = r^n, we have ...
r^n -k²r^(n-2) = 0
r^(n-2)(r² -k²) = 0
r² -k² = 0
r = ±k
a[n] = p·(-k)^n +q·k^n . . . . . . for some constants p and q
We find p and q from the initial conditions.
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f) k² = 4, so k = 2.
a[0] = 0 = p + q
a[1] = 4 = -2p +2q
Dividing the second equation by 2 and adding the first, we have ...
2 = 2q
q = 1
p = -1
The solution is a[n] = -(-2)^n +2^n.
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g) k² = 1/4, so k = 1/2.
a[0] = 1 = p + q
a[1] = 0 = -p/2 +q/2
Multiplying the first equation by 1/2 and adding the second, we get ...
1/2 = q
p = 1 -q = 1/2
Using k = 2^-1, we can write the solution as follows.
The solution is a[n] = (1/2)((-2)^-n +2^-n).
he would be born june 12 1962
10(3) + 3 = 33 times in 2 minutes
10(120) + 3 = 1203 times in 2 hours
