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Damm [24]
4 years ago
11

Multiplying a trinomial by a trinomial follows the same steps as multiplying a binomial by a trinomial. Determine the degree and

maximum possible number of terms for the product of these trinomials: (x2 + x + 2)(x2 – 2x + 3). Explain how you arrived at your answer.
Mathematics
1 answer:
charle [14.2K]4 years ago
6 0
To determine the degree of the product of the given trinomials, you would multiply the term with the highest degree of each trinomial together. Both trinomials are degree 2, and when you multiply x2<span> by </span>x2<span>, you add the exponents to get </span>x4<span>. Thus, the degree of the product is 4. If the product is degree 4, and there is only one variable, the maximum number of terms is 5. There can be an </span>x4<span> term, an </span>x3<span> term, an </span> x2<span> term, an </span>x<span> term, and a constant term. </span>
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A jewelry store is having a going-out-of-business sale. All merchandise is marked 40% off the regular price. The regular price o
Anit [1.1K]

Answer:

$35.97

Step-by-step explanation:

the regular price is 59.95

40% discount so

let's say the price now is x and i am gonna do fractions

x/59.95 = 40%/100

100 x X = 100x  

59.95 x 40 = 2398

i divide 2398 by 100 which equal 23.98

40% is 23.98 and then i do 59.95 - 23.96 = 35.97

DONE!

8 0
4 years ago
Find e^cos(2+3i) as a complex number expressed in Cartesian form.
ozzi

Answer:

The complex number e^{\cos(2+31)} = \exp(\cos(2+3i)) has Cartesian form

\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2).

Step-by-step explanation:

First, we need to recall the definition of \cos z when z is a complex number:

\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}.

Then,

\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}. (I)

Now, recall the definition of the complex exponential:

e^{z}=e^{x+iy} = e^x(\cos y +i\sin y).

So,

e^{2i-3} = e^{-3}(\cos 2+i\sin 2)

e^{-2i+3} = e^{3}(\cos 2-i\sin 2) (we use that \sin(-y)=-\sin y).

Thus,

e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)

Now we group conveniently in the above expression:

e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2.

Now, substituting this equality in (I) we get

\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2.

Thus,

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right].

5 0
3 years ago
When 5 is added to 2 times a number, the result is 45. find the number.
WINSTONCH [101]
A.

let the number be n.
2n+5=45
2n=40
n=20
3 0
3 years ago
Look at the image to answer.​
Katen [24]

The correct answer is D

since 3.2222... is a repeating number, it is rational

0.112123123412345 is not repeating and doesn't have a cosistent pattern, so it isn't rational

1.589 is rational because this decimal stops and doesn't continue- it can also be written as a fraction ( \frac{1589}{1000} )

8 0
4 years ago
In a race, Andrew ran 4 minutes less than 4 times as many minutes as Chris ran. Write an expression to represent the number of m
Aleksandr [31]

Answer:

4y - 4

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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