All categories

3 years ago

The largest exponent in a polynomial is called its _____.

Mathematics

2 answers:

Galina-37 [17]3 years ago

8 0

This is called the leading term

nasty-shy [4]3 years ago

6 0

Answer:Degree of a polynomial :)

You might be interested in

Solve for x:<br> 1 1/5x−2 1/3<1/7x+1 1/2

Mashcka [7]

Answer: $x$

Step-by-step explanation:

$1\frac{1}{5}x-2\frac{1}{3}$

Add $2\frac{1}{3}$ on both sides and subtract $\frac{1}{7}x$ on both sides to leave x's on the left side and independent values on the right.

$(2\frac{1}{3}-\frac{1}{7}x) +1\frac{1}{5}x-2\frac{1}{3}$

$1\frac{1}{5}x-\frac{1}{7}x$

Solve the fractions.

$1(\frac{1}{5}-\frac{1}{7})x$

$1(\frac{(1)(7)-(5)(1)}{(5)(7)} )x$

$1(\frac{7-5}{35} )x$

$1(\frac{2}{35} )x$

$1\frac{2}{35}x$

Convert the mixed fraction $1\frac{2}{35}$ to an improper fraction. You can do this by multiplying 1 times 35 and adding 2.

$\frac{37}{35}x$

Now use the reciprocal (inverse fraction) and multiply on both sides to isolate x.

$(\frac{35}{37}) (\frac{37}{35})x$

$x$

5 0

3 years ago

Please help me solve this problem... I will mark you brainliest

AVprozaik [17]

Answer:

(8,1)

Step-by-step explanation:

3 0

3 years ago

Please help! I’ll mark brainliest

OLga [1]

The answer would be 6

8 0

2 years ago

How many diagonals can be constructed from one vertex of an n-gon? State your answer in terms of n and, of course, justify your

Rasek [7]

Polygon Diagonals. The number of diagonals in a polygon = n(n-3)/2, where n is the number of polygon sides. For a convex n-sided polygon, there are n vertices, and from each vertex you can draw n-3 diagonals, so the total number of diagonals that can be drawn is n(n-3).

3 0

2 years ago

Help me assapppp!!! Pls

mafiozo [28]

Answer:

have you tries adding them together?

5 0

3 years ago