List the 3-membered subsets of the set {1,2,3,4,5,6).

Please help me with my math

ValentinkaMS [17]

Im failing math but passing all others im sorry lol

7 0

3 years ago

Use the game spinner for questions 1-4. In your final answer, include all necessary calculations.

IrinaVladis [17]

Answer:

P (Even number) = 1/2

P(spinner will land on an odd number) = 1/2

P(spinner will not land on 2 or 3) = 3/4

P(spinner will not land on a multiple of 3) = 3/4

Step-by-step explanation:

Here, while spinning the spinner total possible outcomes

are 8 = {1,2,3,4,5,6,7,8}

Now, $\textrm{P(E)} = \frac{\textrm{Number of favorable outcomes }}{\textrm{Total numberof outcomes}}$

a) E: Probability of getting even number

Favorable outcomes are {2,4,6,8}

Hence, $P(E) = \frac{4}{8} = \frac{1}{2}$

b)E: Probability that the spinner will land on an odd number.

Favorable outcomes are {1,3,5,7}

Hence, $P(E) = \frac{4}{8} = \frac{1}{2}$

c) E: Probability that the spinner will not land on 2 or 3

Favorable outcomes are {1, 4,5,6,7,8}

Hence, $P(E) = \frac{6}{8} = \frac{3}{4}$

d) E: Probability that the spinner will not land on a multiple of 3

Favorable outcomes are {1,2,4,5,7,8}

Hence, $P(E) = \frac{6}{8} = \frac{3}{4}$

3 0

2 years ago

Solve the system of equations by transforming a matrix representing the system of equation into reduced row echelon form.

Gekata [30.6K]

Take the augmented matrix,

$\left[\begin{array}{ccc|c}2&1&-3&-20\\1&2&1&-3\\1&-1&5&19\end{array}\right]$

Swap the row 1 and row 2:

$\left[\begin{array}{ccc|c}1&2&1&-3\\2&1&-3&-20\\1&-1&5&19\end{array}\right]$

Add -2(row 1) to row 2, and -1(row 1) to row 3:

$\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&-3&4&22\end{array}\right]$

Add -1(row 2) to row 3:

$\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&9&36\end{array}\right]$

Multiply through row 3 by 1/9:

$\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&1&4\end{array}\right]$

Add 5(row 3) to row 2:

$\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&0&6\\0&0&1&4\end{array}\right]$

Multiply through row 2 by -1/3:

$\left[\begin{array}{ccc|c}1&2&1&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]$

Add -2(row 2) and -1(row 3) to row 1:

$\left[\begin{array}{ccc|c}1&0&0&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]$

So we have $\boxed{x=-3,y=-2,z=4}$ .

3 0

3 years ago

Can someone help me with this please

Pepsi [2]

Answer:

63.6

Step-by-step explanation:

$\sqrt{45^{2} + 45^{2}} = \sqrt{4050}$

3 0

3 years ago

Read 2 more answers

Kayleigh babysat for 11 hours this week that was 5 fewer than 2/3 as manyas she baby sat last week, h write an equation to repre

mars1129 [50]

Answer:

10.5 hours

Step-by-step explanation:

To find the number of hours she babysat last week subtract 5 from 11 which is 7 hours. 7 hours is equal to 2/3 of the many hours. If she babysat h hours last week then solve for h using 2/3 h = 7.

Solve the equation by multiplying each side by the reciprocal.

3/2 * 2/3h = 7*3/2

h = 21/2

h = 10.5 hours

3 0

3 years ago