I would start by saying how much I enjoyed this lesson and how it has helped me in many ways I would also like to state how it was difficult at first but once I started to understand it, it became really easy and would like to thanks the teacher for teaching it.
The options Patel has to solve the quadratic equation 8x² + 16x + 3 = 0 is x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot.
<h3>Quadratic equation</h3>
8x² + 16x + 3 = 0
8x² + 16x = -3
8(x² + 2x) = -3
- Using completing the square
8(x² + 2x + 1) = -3 + 8
8(x² + 1) = 5
(x² + 1) = 5/8
- Taking the square root of both sides
(x + 1) = ± √5/8
x = -1 ± √5/8
Therefore,
x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot
Learn more about quadratic equation:
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Answer:
y = (-1/2)x + 21/2
Step-by-step explanation:
Given equation:
y - 2x + 7
Coordinates = (5,8)
Find:
Perpendicular equation
Computation:
y = mx + c
y - 2x + 7
y = 2x - 7
So,
m = 2
The negative reciprocal of 2 is -1/2
So,
For,
Coordinates = (5,8)
y = mx + c
8 = (-1/2)(5) + c
8 = -5/2 + c
c = 8 + 5/2
c = 21 /2
So,
y = mx + c
y = (-1/2)x + 21/2
