First question seems incomplete :
Answer:
40 ways
Step-by-step explanation:
Question B:
Number of boys = 6
Number of girls = 4
Number of people in committee = 3
Number of ways of selecting committee with atleast 2 girls :
We either have :
(2 girls 1 boy) or (3girls 0 boy)
(4C2 * 6C1) + (4C3 * 6C0)
nCr = n! ÷ (n-r)!r!
4C2 = 4! ÷ 2!2! = 6
6C1 = 6! ÷ 5!1! = 6
4C3 = 4! ÷ 1!3! = 4
6C0 = 6! ÷ 6!0! = 1
(6 * 6) + (4 * 1)
36 + 4
= 40 ways
Answer:
195
Step-by-step explanation:
78/2*5
Answer:
a
Step-by-step explanation:
use ur brain
Answer:
+ 3x +9x +27 = 0
x(x+3)+9(x+3)=0
(x+3)(x+9)=0
x=-3, x=-9
Step-by-step explanation:
a=1 b=12 c=27
sum=12
factor=27x 1
3x9
also 3+9=12