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2 years ago

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Johnny biked at a steady rate of 15 miles per hour for 2 hours. Does the graph of this linear relationship represent a discrete

(a set of unconnected points) or a continuous (solid) relationship?

1 answer:

Margarita [4]2 years ago

4 0

Answer:

solid

Step-by-step explanation:

he biked at a steady rate of 7.5 miles per hour

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Show me the work and answer please

BARSIC [14]

A quick way to answer all 1-10 is to multiply the starting price by 1.##. So for number 1 the equation would be 18 x 1.07 which equals $19.26. Question 2 would be
14 x 1.20 which equals $16.80. I think you got it from here.

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2 years ago

Ruth buys 19 identical tickets for £280.25.<br> Estimate the cost of one ticket.

xxTIMURxx [149]

Answer:

The cost of one ticket is $14.75

Step-by-step explanation:

To find the cost of one ticket we need to divide 280.25 by 19

=$14.75

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2 years ago

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Alex

Answer:

Last option.

Step-by-step explanation:

The consecutive exterior angle theorem states that the exterior angles are supplementary if two lines are cut by a transversal.

m∠1 + m∠7 = 180

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2 years ago

7 3/4 + (12 - 3 6/11) =

nataly862011 [7]

Answer:

$\frac{713}{44} = 16 \frac{9}{44}$

Step-by-step explanation:

7 3/4+ (12 - 3 6/11)

31/4 + (12 - 3 6/11)

31/4 + (12 - 39/11)

31/4 + 93/11

= <u>7</u><u>1</u><u>3</u><u>/</u><u>4</u><u>4</u><u> </u><u>=</u><u> </u><u>1</u><u>6</u><u> </u><u>9</u><u>/</u><u>4</u><u>4</u>

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2 years ago

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Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat

yulyashka [42]

Answer:

The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

$P(t) = 0.8t^{2} + 6t + 19000$

In what month and year will the population reach 34,200?

We have to find t for which P(t) = 34200. So

$P(t) = 0.8t^{2} + 6t + 19000$

$0.8t^{2} + 6t + 19000 = 34200$

$0.8t^{2} + 6t - 15200 = 0$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$0.8t^{2} + 6t - 15200 = 0$

So $a = 0.8, b = 6, c = -15200$

Then

$\bigtriangleup = 6^{2} - 4*0.8*(-15100) = 48356$

$t_{1} = \frac{-6 + \sqrt{48356}}{2*0.8} = 134.14$

$t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64$

We only take the positive value.

134 years after 2012.

.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

6 0

2 years ago