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OleMash [197]
4 years ago
9

A bowl contains 4 yellow marbles and 3 red marbles. Michael randomly draws 4 marbles from the bowl. He replaces each marble afte

r it is drawn. What is the probability that he draws 3 yellow marbles and 1 red marble.
A. 12/35
B. 3/35
C. 192/2401
D. 768/2401
Mathematics
1 answer:
ra1l [238]4 years ago
5 0
So each event is indipentent of each other
chance=(desired outcomes)/(total possible outcomes)
3+4=7
7=total outcomes
3red
4yellow
so each time there is a 3/7 chance of drawing a red marble and a 4/7 chance of
red=3/7
yellow=4/7

so 3 yellow marbles and 1 red=4/7 times 4/7 times 4/7 times 3/7=(4^3 times 3)/(7^4)=192/2401 which is C

the answer is C 192/2401
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\huge\textsf{Hey there!}

\mathsf{2x^2 + 3x - 12}

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\boxed{\boxed{\huge\textsf{Answer: \bf 53}}}\huge\checkmark

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Check the picture below.

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