Answer:
t ≤ 4x + 10
Step-by-step explanation:
The amount of money that Josh spends on rides is the variable T, found in the problem. Josh wants to spend AT MOST t. That means he can spend as little as he wants, but he can't ride too many times so that the cost goes over T. Therefore, it has to be less than. But, it can also be equal to, as he can ride exactly many rides up to T, it just can't go over it.
Next, the cost to get into the fair is ten dollars, meaning if he goes on only one ride, that will cost him 4 dollars, but actually will have cost him 14 dollars because of the entrance fee. So, no matter how many rides he goes on, there is always the entrance fee added on.
Finally, the cost for each ride is 4 dollars per ride or 4 times x with x being the number of rides he goes on.
So, for our answer, we have t ≤ 4x + 10!
Answer:
= -3 (x-y)
Step-by-step explanation:
-5x - 4y + 2x + 7y
Collect the like terms by calculating the sum or difference of their coefficients
(-5+2)x
-3x
(-4+7)y
3y
-3x + 3y
Factor out -3 from the expression
-3 (x-y)
Answer:
0.665
Step-by-step explanation:
Given: 100 people are split into two groups 70 and 30. I group is given cough syrup treatment but second group did not.
Prob for a person to be in the cough medication group = 0.70
Out of people who received medication, 34% did not have cough
Prob for a person to be in cough medication and did not have cough
=
Prob for a person to be not in cough medication and did not have cough
=
Probability for a person not to have cough
= P(M1C')+P(M2C')
where M1 = event of having medication and M2 = not having medication and C' not having cough
This is because M1 and M2 are mutually exclusive and exhaustive
SO P(C') = 0.397+0.2=0.597
Hence required prob =P(M1/C') = 
<h3>Answer is -9</h3>
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Work Shown:
(g°h)(x) is the same as g(h(x))
So, (g°h)(0) = g(h(0))
Effectively h(x) is the input to g(x). Let's first find h(0)
h(x) = x^2+3
h(0) = 0^2+3
h(0) = 3
So g(h(x)) becomes g(h(0)) after we replace x with 0, then it updates to g(3) when we replace h(0) with 3.
Now let's find g(3)
g(x) = -3x
g(3) = -3*3
g(3) = -9
-------
alternatively, you can plug h(x) algebraically into the g(x) function
g(x) = -3x
g( h(x) ) = -3*( h(x) ) ... replace all x terms with h(x)
g( h(x) ) = -3*(x^2 + 3) ... replace h(x) on right side with x^2+3
g( h(x) ) = -3x^2 - 9
Next we can plug in x = 0
g( h(0) ) = -3(0)^2 - 9
g( h(0) ) = -9
we get the same result.
