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ohaa [14]
3 years ago
14

What is the algebraic rule?

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
8 0
The answer is 5 for this question
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What Should i write down basically i just need the answers and let me copy and paste
Anastaziya [24]

Answer:

✔️Ratio of weight to mass in simplest form: 49/5 or 49 : 5

✔️x = 110

Step-by-step explanation:

Since the ratio of weight to mass is constant, therefore we can use any pair of values from the table to find the ratio that represents the table. Let's pick the first row:

(20, 196)

Ratio of weight to mass = 196 : 20

= 196/20

= 49/5

Or 49 : 5

✔️Let's use this ratio/proportion to find x in the table

Ratio of weight to mass = 49:5

Thus:

1078/x = 49/5

Cross multiply

x*49 = 1078*5

49x = 5,390

x = 5,390/49

x = 110

5 0
2 years ago
Can anyone help me plz​
Kryger [21]

Answer:Ok

You need to get x by itself.

8x + c = k

Subtract c.

8x = k - c

Divide 8 from both sides.

x = k - c / 8

So, I believe it is D

Step-by-step explanation:

4 0
3 years ago
Please answer my question!
Salsk061 [2.6K]

D is not a terminating decimal because it repeats *hint the dash mark above the 4*

6 0
2 years ago
If a1=6 and an=2an-1 then find the value of a4
Grace [21]
The absolute value be pie or square because Pio screwed because the circumference is alsoHope this helps
5 0
2 years ago
What is the area of a sector that has a radius of 25 mm and has an angle measure of 50°?
Nimfa-mama [501]

The area of the sector is 86.81π mm²

<u>Explanation:</u>

Given:

Radius of the sector, 25mm

Angle, α = 50°

Area of the sector, A = ?

We know:

Area of the sector = \frac{\alpha }{360} X \pi r^2

On substituting the value, we get:

A = \frac{50}{360} X \pi X (25)^2\\\\A = 86.81 \pi mm^2

Therefore, the area of the sector is 86.81π mm²

3 0
3 years ago
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