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Dafna1 [17]
3 years ago
6

Can anyone figure this out for me please? It would be greatly appreciated.

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
8 0
Check the picture below.

now, to get how much is the area of the tiled section, we simply get the area of the whole pool, 53x26, which includes the tiles, and then subtract the area without the tile, the rectangle in the middle, and what's leftover, is the area of the tiled area.

\bf 53-4\frac{1}{2}-4\frac{1}{2}\implies 53-9\implies \boxed{42}
\\\\\\
26-4\frac{1}{2}-4\frac{1}{2}\implies 26-9\implies \boxed{17}
\\\\\\
\textit{so the area of the rectangle in the middle is}\implies 42\cdot 17\implies 714
\\\\\\
\textit{and the area of the whole pool is}\implies 53\cdot 26\implies 1378

\bf \stackrel{\textit{area of the whole pool}}{1378}~~-~~\stackrel{\textit{area of the middle rectangle}}{714}\implies \stackrel{\textit{area of the tiles}}{664}\\\\
-------------------------------\\\\
\textit{we know that is }\$5\frac{1}{2}\textit{ for a foot of tile, then}\stackrel{\textit{price of the tiles}}{664\cdot 5\frac{1}{2}}\implies 3652

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Answer:

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Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
How Can you divide that
Archy [21]
First you ask yourself, can 8 go into 1?  The answer is no.  Can 8 go into 12? Yes, 1 time.  So you put 1 on top of the 2 and subtract 8 from 12.  That gives you 4.  Then you pull down the 8 from 128 and ask how many times can 8 go into 48?  The answer is 6.  So your answer is 16.  Hope I helped!

6 0
3 years ago
Read 2 more answers
Help me please i cant get it
Leni [432]

Answer:

Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.

The total cost of both games is:

X + Y

We know that both games cost just above AED 80

Then:

X + Y > AED 80

From this, we want to prove that at least one of the games costed more than AED 40.

Now let's play with the possible prices of X, there are two possible cases:

X is larger than AED 40

X is equal to or smaller than AED 40.

If X is more than AED 40, then we have a game that costed more than AED 40.

If X is less than or equal to AED 40, then:

X ≥ AED 40

Now let's take the maximum value of X in this scenario, this is:

X = AED 40

Replacing this in the first inequality, we get:

X + Y > AED 80

Replacing the value of X we get:

AED 40 + Y  > AED 80

Y > AED 80 - AED 40

Y > AED 40

So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.

So we proven that in all the possible cases, at least one of the two games costs more than AED 40.

7 0
3 years ago
5=2/3x what does x equal
mixer [17]

Answer:

I dont know if u mean 5 equals 2 divided by 3x, but I got 2/15

Step-by-step explanation:

3 0
2 years ago
Which is a simplified form of the expression -4(3r – 2) – 2(r + 1)?
Delicious77 [7]

Answer:

2 (3 - 7 r)

Step-by-step explanation:

Simplify the following:

-4 (3 r - 2) - 2 (r + 1)

-4 (3 r - 2) = 8 - 12 r:

8 - 12 r - 2 (r + 1)

-2 (r + 1) = -2 r - 2:

-12 r + -2 r - 2 + 8

Grouping like terms, -2 r - 12 r - 2 + 8 = (8 - 2) + (-12 r - 2 r):

(8 - 2) + (-12 r - 2 r)

-12 r - 2 r = -14 r:

-14 r + (8 - 2)

8 - 2 = 6:

6 - 14 r

Factor 2 out of 6 - 14 r:

Answer: 2 (3 - 7 r)

6 0
3 years ago
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