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amm1812
2 years ago
7

Ann spent 1/3 of her money on transport, 2/5 on food, 1/6 on clothing and saved $80.00. How much money did she have to begin wit

h?
Mathematics
1 answer:
yKpoI14uk [10]2 years ago
5 0

Answer:

Her initial money she started with us $800.00

Step-by-step explanation:

Let the initial money Ann began with be x.

So she spent 1/3 of x on transport,

2/5 of x on food

1/6 of x on clothing

And the remaining is $80.00.

Let's find the value of x

X(1/3) +x(2/5) + x(1/6) +80 = x

X(1/3) +x(2/5) + x(1/6) -x = -80

Taken 30 as the lowest common multiple of the factors gives

(10x + 12x + 5x -30x)/30 = -80

(10x + 12x + 5x -30x)= -2400

-3x = -2400

X = -2400/-3

X= 800

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The correct answer is C) t₁ = 375, t_n=5t_{n-1}.

From the general form,
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The general form is derived from the explicit form, which is
t_n=t_1(r)^{n-1}.  We can see that r = 5; 5 has the exponent, so that is what is multiplied by every time. This gives us

t_n=t_1(5)^{n-1}

Using the products of exponents, we can "split up" the exponent:
t_n=t_1(5)^n(5)^{-1}

We know that 5⁻¹ = 1/5, so this gives us
t_n=t_1(\frac{1}{5})(5)^n
\\
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Comparing this to our general form, we see that
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Multiplying by 5 on both sides, we get that
t₁ = 75*5 = 375

The recursive formula for a geometric sequence is given by
t_n=t_{n-1}(r), while we must state what t₁ is; this gives us

t_1=375; t_n=t_{n-1}(5)

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3 years ago
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