Answer:
ABQ = 139
BCR is the same as QBC since they are alternate interior angles
BCR = 41
Step-by-step explanation:
CBQ and SCB are same side interior angles so they add to 180
2a-9 + 5a +14 = 180
Combine like terms
7a +5 = 180
Subtract 5 from each side
7a = 175
Divide by 7
7a/7 = 175/7
a = 25
ABQ is the same as SCB since they are corresponding angles so
ABQ = SCB = 5a+14 = 5*25+14 = 125+14 = 139
BCR is the same as QBC since they are alternate interior angles
BCR = QBC = 2a-9 = 2*25 -9 = 50-9 = 41
Answer: D
Step-by-step explanation: start at y-axis and go over 5, down 1 since its a -1.
Given:
A regular polygon with three vertices and side 14 cm.
To find:
Area of the regular polygon.
Solution:
We know that, a regular polygon has equal sides and equal interior angles.
The given regular polygon has three equal sides, it means it is an equilateral triangle.
The area of an equilateral triangle is:

Where, a is the side length of the triangle.
Putting
, we get




Therefore, the area of given regular polygon is 84.9 cm².