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Naddika [18.5K]
3 years ago
11

Noah spins 2 spinners at the same time. Each spinner is numbered 1 through 4. If each spinner can land only in one of the number

ed sections (not on a line), which list represents the sample space?
Select one:

List C

List B

List A

List D
Mathematics
2 answers:
Simora [160]3 years ago
5 0

Um, what are the lists look like? Step-by-step explanation:

Yuri [45]3 years ago
4 0
List b? (Don’t mind this texting)
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Using algebra, find the point at which the line k(x) = 5x - 1 intersects with the line h(x) = -3x - 1 ?
vichka [17]

The point at which the lines k(x) = 5x - 1 and h(x) = -3x - 1 meet is (0, -1)

Given: k(x) = 5x - 1, h(x) = -3x - 1

We need to find the point(if any) at which these two lines k and h meets.

To find point of intersection(if any), we need to set the functions equal as at the point of intersection the (x, y) value will be same for both of the lines.

Therefore, k(x) = h(x)

=> 5x - 1 = -3x - 1

=> 8x = 0

=> x = 0

k(x=0) = 5 * 0  - 1 = -1

Hence the point at which the lines k(x) = 5x - 1 and h(x) = -3x - 1 meet is (0, -1)

Know more about "point of intersection" problems here: brainly.com/question/16929168

#SPJ1

8 0
2 years ago
Hellppppp!!! please??
Wewaii [24]
X1 y4 x 6 and x 6 y 4
5 0
3 years ago
Read 2 more answers
A $104.000 selling price with $24000 down at 8 1/2% for 25 years results in a monthly payment of
romanna [79]
*******************************************************
(See attached formula)
Loan Principal = 104,000 - 24,000 = 80,000
rate = 8.5 / 1,200  = <span> <span> <span> 0.0070833333 </span> </span> </span>
time = 25 years = 300 months

Monthly Payment = <span> <span> 0.0070833333 </span> + </span><span> <span> [ 0.0070833333 / ((1</span></span><span>.0070833333)^300 -1)) ] *principal
</span>
Monthly Payment = <span>0.0070833333 + </span><span> [ 0.0070833333 / (</span><span> </span> <span> <span> <span> 8.3104129461 </span> </span> </span> -1)] * 80,000
Monthly Payment = 0.0070833333 + [ 0.0070833333 / ( 7.3104129461)] * 80,000
Monthly Payment = (0.0070833333 + <span> <span> <span> 0.00096893750767) * 80,000
</span></span></span>Monthly Payment = <span> <span> <span> 0.00805227080767 </span> </span> </span> * 80,000
Monthly Payment = <span> <span> <span> 644.18

Source:
http://www.1728.org/calcloan.htm

</span></span></span>

3 0
3 years ago
Use the Distributive Property to write -3x-4x in factored form
Alchen [17]
-x(3+4) 

If you distribute it to all the numbers the simplest form would be -3x-4x 
5 0
4 years ago
Three times each day, a quality engineer samples a component from a recently manufactured batch and tests it. Each part is class
Tresset [83]

Answer:

Step-by-step explanation:

Hello!

Three samples of components manufactured are taken per day. They are classified as:

D: "Conforming (suitable for its use)"

E: "Downgraded (unsuitable for the intended purpose but usable for another purpose)"

F: "Scrap (not usable)"

This classification includes the three events that may occur in your sample space S. The experiment consists in recording the categories of the three parts tested in a day.

a. List the 27 outcomes in the sample space.

The possible outcomes in the space sample are the combinations of the three events. To avoid using the same letters as in the following questions I've named the evets as D, E, and F

S={DDD, DED, DFD, DEF, DFE, DEE, DFF, DDE, DDF , EDE, EEE, EFE, EED, EEF, EDF, EFD, EDD, EFF , FDF, FEF, FFF, FFE, FFD, FDE, FED, FDD, FEE}

b. Let A be the event that all the parts fall into the same category. List the outcomes in A.

A: "All the parts fall into the same category"

You have three possible outcomes for this event, that the three compounds are conforming, "DDD", that the three are unconforming, "EEE", or that the three compounds are scrap, "FFF". There are only three possible outcomes for this event.

S={DDD, EEE, FFF}

c. Let B be the event that there is one part in each category. List the outcomes in B.

B: "There is a part in each category"

This means, for example, The first one is conforming "D", the second one is unconforming "E" and the third one is scrap "F", then the first one may be unconforming "E", the second one is conforming "D" and the thirds one is scrap "F", and so on, you have 6 possible outcomes for this event:

S={DEF, DFE, EDF, EFD, FDE, FED}

d. Let C be the event that at least two parts are conforming. List the outcomes in C.

C: "At least two parts are conforming"

For this event, you can have two of the compounds to be considered conforming or the three of them.

S={DDD, DED, DFD, DDE, DDF , EDD, FDD}

A total of 7 combinations fit this event.

I hope you have a SUPER day!

6 0
3 years ago
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