Ex.
f + g = y
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3
3(f+g) = (y) 3
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3
f + g =3y
f - f + g = 3y - f
g = y - f
Answer:
If m is nonnegative (ie not allowed to be negative), then the answer is m^3
If m is allowed to be negative, then the answer is either |m^3| or |m|^3
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Explanation:
There are two ways to get this answer. The quickest is to simply divide the exponent 6 by 2 to get 6/2 = 3. This value of 3 is the final exponent over the base m. Why do we divide by 2? Because the square root is the same as having an exponent of 1/2 = 0.5, so
sqrt(m^6) = (m^6)^(1/2) = m^(6*1/2) = m^(6/2) = m^3
This assumes that m is nonnegative.
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A slightly longer method is to break up the square root into factors of m^2 each and then apply the rule that sqrt(x^2) = x, where x is nonnegative
sqrt(m^6) = sqrt(m^2*m^2*m^2)
sqrt(m^6) = sqrt(m^2)*sqrt(m^2)*sqrt(m^2)
sqrt(m^6) = m*m*m
sqrt(m^6) = m^3
where m is nonnegative
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If we allow m to be negative, then the final result would be either |m^3| or |m|^3.
The reason for the absolute value is to ensure that the expression m^3 is nonnegative. Keep in mind that m^6 is always nonnegative, so sqrt(m^6) is also always nonnegative. In order for sqrt(m^6) = m^3 to be true, the right side must be nonnegative.
Example: Let's say m = -2
m^6 = (-2)^6 = 64
sqrt(m^6) = sqrt(64) = 8
m^3 = (-2)^3 = -8
Without the absolute value, sqrt(m^6) = m^3 is false when m = -2
X+y=156
<span>0.05x+0.25y=21.6
-1/4*/ x+y=156
1/20x+1/4y=216/10
-1/4x-1/4y=156*-1/4=-39
</span>1/20x+1/4y=216/10
<span>+--------------------------
-4/20x=-17,4
x=87
</span>x+y=156
<span>
87+y=156 y=69
this question answer is </span><span>87 nickels and 69 quarters</span><span>
</span>
What are the measurements?
first isolate y so it is in slope intercept formula:
8x-3y=9
Subtract 8x from both sides
8x - 8x - 3y= 9 - 8x
-3y = 9 - 8x
Now divide both sides by -3 to isolate y
-3/-3y = 9/(-3) - 8x/(-3)
y = -3 + 8/3x
y = 8/3x - 3
Slope: 8/3
Hope it helps :)
branliest would be appreciated
