A round trip is twice the distance herein;
So, (280*2) feet
=560 feet
Answer:
(3X8) - 4 + 2 - 12
Step-by-step explanation:
Following the order of operations solve:
(24) - 4 + 2 - 12
20 + 2 - 12
22 - 12
10
Don't feel bad, this is an odd question and the parenthesis do not seem to be required. Following the order of operations would result in the same answer anyway...
Odd.
Answer:
360 mi/h
Step-by-step explanation:
The speed for the outbound trip was ...
speed = distance/time = (715 mi)/(2 1/6 h) = 330 mi/h
The inbound speed was ...
(715 mi)/(1 5/6 h) = 390 mi/h
The airspeed of the plane is the average of these two ground speeds, so is ...
(330 +390)/2 = 360 . . . . mi/h
Answer:
442 miles
Step-by-step explanation:
Given
To properly solve this question, I illustrate some given parameters using attached image
From the image, apply Pythagoras theorem

Differentiate w.r.t time (t)


Divide both sides by 2

From the question, we have that the plan travels are 510mi/h.
This implies that:

So, we then calculate the value of x when the distance (y) is 2mi i.e.:

Apply Pythagoras theorem






So, the expression becomes:








<em>Hence, the distance is 442 miles</em>