(5ab-4a-8)-(9ab-5)
Ok just remember that the minus sign before the (9ab-5) is like a minus 1 so it changes the sign inside the bracket...
>>5ab-4a-8-9ab+5
>>-4ab-4a-3
I'm guessing you just have to leave it like that unless there are other parts to the question or whatever but that's that simplified as far as it can be!
Answer:
The probability that the center will have enough employees to handle this call volume is 0.2764
Step-by-step explanation:
Probability is defined as the ratio of favorable outcomes to the total number of outcomes.
Here the total mean expected number of outcomes=u = 4000
The favorable expected outcomes are = x= 22* 178= 3916
The standard deviation= σ= 5
The random variable X =178 has normal distribution with mean 4000/22 and standard deviation 5
So z= x-u/σ
Z= (3916-4000)/22/5
z= -0.764
From the table of areas under normal curve
P ( x= 3916)= P( -0.764 ≤ Z≤ 0)
P ( x= 3916)= 0.2764
The probability that the center will have enough employees to handle this call volume is 0.2764
10 seats are nonsplash zone
18-8=10 because there are 18 total seats and 8 splash zone seats just subtract them Hope this helped :)
15m ^3 - 26m^2 +11m - 4 is the result of the product.
(5m^2 -2m +1)(3m-4)
On opening the bracket, we multiply the terms,
= 15m^3 -6m^2 +3m -20m^2+8m -4
= 15m ^3 - 26m^2 +11m - 4
This is the result of the product
When we mutiply the two equations.
QUESTION 1
The given system of equations are:
We equate the two equations to get:
When x=0,
The solution is (0,1)
QUESTION 2
The given equations are:
and
We equate both equations to get:
Group similar terms,
We put x=0 into any of the equations to find y.
The solution is (0,-1).
QUESTION 3
The given equations are:
and
We equate both equations:
Group similar terms:
This is not true.
Hence the system has no solution.
