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4 years ago

A number is rounded to the nearest tenth and hundredth. What is the number that was rounded? (2 points)

Mathematics

1 answer:

Butoxors [25]4 years ago

5 0

Answer:

Step-by-step explanation:

For the tenths, if the hundredths digit is above 5, it rounds up. 7 is greater than 5, so it rounds the whole number to 0.6

For the hundredths, if the thousandths number is greater than 5, it rounds up. 8 is greater than 5, so it rounds the whole number to 0.58

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Solve 2/3 x - 4 = -2

marta [7]

Answer:

- 9

Step-by-step explanation:

2/3 x - 4 = -2

2/3 x = -2+4

x = 6 * (-3/2)

9 = -9

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3 years ago

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How can you calculate the circumference if you know the circle’s radius? Write a formula please.

Alika [10]

C=2πR
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3 years ago

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WILL MARK BRAINLIEST '<br> IF YOU DONT KNOW DONT ANSWER

Soloha48 [4]

Answer: A) Alternate Exterior

Step-by-step explanation:

Let's find out the defenition of alternate exterior; "If a pair of parallel lines are cut by a transversal line, then the alternate exterior angles are congruent".

I hope this helps!

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3 years ago

A) 2 / 7 + 3 / 7 = ? b) 5 / 8 + 7 / 8 = ? c) 2 / 3 - 1 / 2 = ?

sergeinik [125]

Answer: A=5/7. B=3/2. C=1/6

D=3/5. E=14/11. G=5/7 H=3/2 I=1/6 j=3/5 K=14/11 L=7/8

Step-by-step explanation:

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3 years ago

In a study to compare two different corrosion inhibitors, specimens of stainless steel were immersed for four hours in a solutio

djverab [1.8K]

Answer:

$(242-220) -1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 10.862$

$(242-220) +1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 33.138$

And the 95% confidence interval for the difference in the means is given by: $10.862 \leq \mu_A -\mu_B \leq 33.138$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_A = 242$ sample mean for inhibitor A

$s_A = 20$ sample standard deviation for inhibitor A

$n_A = 47$ sample size for A

$\bar X_B = 220$ sample mean for inhibitor B

$s_B = 31$ sample standard deviation for inhibitor B

$n_B = 42$ sample size for A

Solution to the problem

For this case the confidence interval for the difference of means is given by:

$(\bar X_A -\bar X_B) \pm t_{\alpha/2} \sqrt{\frac{s^2_A}{n_A} +\frac{s^2_B}{n_B}}$

The degrees of freedom are given by:

$df = n_A +n_B -2 = 47+42-2= 87$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,87)".And we see that $t_{\alpha/2}=1.988$

And replacing we got:

$(242-220) -1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 10.862$

$(242-220) +1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 33.138$

And the 95% confidence interval for the difference in the means is given by: $10.862 \leq \mu_A -\mu_B \leq 33.138$

4 0

3 years ago