Step-by-step explanation:
look at the pic................... hope it helps
h(t)=(t+3) 2 +5 h, left parenthesis, t, right parenthesis, equals, left parenthesis, t, plus, 3, right parenthesis, squared, plu
lesya692 [45]
Answer:
1
Step-by-step explanation:
If I understand the question right, G(t) = -((t-1)^2) + 5 and we want to solve for the average rate of change over the interval −4 ≤ t ≤ 5.
A function for the rate of change of G(t) is given by G'(t).
G'(t) = d/dt(-((t-1)^2) + 5). We solve this by using the chain rule.
d/dt(-((t-1)^2) + 5) = d/dt(-((t-1)^2)) + d/dt(5) = -2(t-1)*d/dt(t-`1) + 0 = (-2t + 2)*1 = -2t + 2
G'(t) = -2t + 2
This is a linear equation, and the average value of a linear equation f(x) over a range can be found by (f(min) + f(max))/2.
So the average value of G'(t) over −4 ≤ t ≤ 5 is given by ((-2(-4) + 2) + (-2(5) + 2))/2 = ((8 + 2) + (-10 + 2))/2 = (10 - 8)/2 = 2/2 = 1
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9514 1404 393
Answer:
angles (W, X, Y) = (77°, 62°, 41°)
Step-by-step explanation:
<u>Given</u>:
ΔWZY
∠W = 2(∠Y) -5°
∠X = ∠Y +21°
<u>Find</u>:
∠X, ∠Y, ∠W
<u>Solution</u>:
Using angle measures in degrees, we have ...
∠X + ∠Y + ∠Z = 180
(∠Y +21) +∠Y + (2(∠Y) -5) = 180
4(∠Y) +16 = 180 . . . . . simplify
∠Y +4 = 45 . . . . . . . . . divide by 4
∠Y = 41 . . . . . . . . . . . . subtract 4
∠W = 2(41) -5 = 77
∠X = 41 +21 = 62
The angle measures of angles (W, X, Y) are (77°, 62°, 41°), respectively.
4x + 15
24 - 8x - 9 + 12x
Add or subtract the common variables
4x + 15
12*5*4.25=255 cubic in (total vol.)
.25*.25*.25=1/64 (vol. of small cube)
255/(1/64)=16,320 cubes
