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noname [10]
3 years ago
8

A bucket contains Soreen tennis balls, 2 yellow tennis balls, and ored tennis balls. Tony

Mathematics
1 answer:
Leni [432]3 years ago
3 0

Answer:

i need to know how many green how many red and if they are replacing the balls or leaving them out

Step-by-step explanation:

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Respond to all of the questions within the topic (see that there are six questions below). 1. Explain how you can determine if t
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Step-by-step explanation:

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In problems 1-3, a and b are legs and c is the hypotenuse. Find the missing side length of the
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Answer:

1. b=39.497

2. c=3.606

3. a=18.974

Step-by-step explanation:

1.

41^2-11^2=b^2

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b^=1560

b=39.497

2.

2^2+3^2=c^2

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3.

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4 0
3 years ago
What is the answer to <br> 8(x-3)+7=2x(4-17)
nadezda [96]

Answer:

x=1/2

Step-by-step explanation:

First you distribute the 8 over the (x-3) giving you 8x-24. Do the same for 2x and (4-17). That should give you 8x-34x.

Your equation should look like : 8x-24+7=8x-34x

Next try to balance out your equation. You want your x's all by themselves in order to solve.

The 8x's cancel eachother out so you have -24+7= -34x.

Add the like terms of -24 and 7 to get -17.

Equation: -17= -34x

Divide both sides by -34 to get x by itself.

-17/-34 = x

Reduce by dividing the numerator and denominator by 17 to get -1/-2

Since they are both negative the fraction turns positive.

So the answer should be x=1/2

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3 years ago
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Answer:

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Step-by-step explanation:

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4 years ago
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LekaFEV [45]

Let s represent the length of any one side of the original square.  The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.

The area of this rectangle is (s+9)(s-2) = 60 in^2.

This is a quadratic equation and can be solved using various methods.  Let's rewrite this equation in standard form:  s^2 + 7s - 18 = 60, or:

s^2 + 7s - 78 = 0.  This factors as follows:  (s+13)(s-6)=0, so that s = -13 and s= 6.  Discard s = -13, since the side length cannot be negative.  Then s = 6, and the area of the original square was 36 in^2.

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3 years ago
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