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tia_tia [17]
3 years ago
14

Throughout this activity, the scale factor, n, has been a positive value. However, a scale factor for dilations can also be nega

tive. When a set of coordinates on a preimage is multiplied by -n instead of n, the coordinates of the image rotate about the center of dilation by 180°. Consider all the potential intervals of n in the table. Enter information in the table to indicate whether the scale factor produces an enlargement, a reduction, or no size change. Also indicate whether the image rotates 180° about the center of dilation. The first one has been done for you.

Mathematics
1 answer:
statuscvo [17]3 years ago
3 0
PLATO , Sample answer had to do it myself through another account so I don’t get scammed, your welcome for future kids

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PLEASE PELASE PLEASE HELP ME
V125BC [204]

Answer:

In ∆ABC AND ∆DEF

ABC=DEF...........each 90°

SIDE AB =SIDE ED...........given

SIDE BC =SIDE EF............B-F-C and E-C-F

∆ABC =∆DEF....................by SAS test

3 0
3 years ago
Learning Task 1: Evaluate the following expressions using GEMDAS or
Vlada [557]

Kabhi Kabhi lagta ha ki apun ich god ha

4 0
3 years ago
Read 2 more answers
Jessie draws triangle ABC on a coordinate grid. The slope of line segment AB is Jessie then transforms triangle
balu736 [363]

Answer:

1) Supports Jessie's Claim

2) Does Not Support Jessi's Claim

3) Supports Jessie's Claim

4) Does Not Support Jessi's Claim

Step-by-step explanation:

The given transformations are;

1) Rotation of 180° around the origin

For a rotation of 180° around the origin, either clockwise or anti clockwise, for a given coordinate of the preimage (x, y), the coordinate of the image is (-x, -y)

Therefore, whereby the slope of the preimage, given two points (0, 0) and (2, 2), = (2 - 0)/(2 - 0) = 1

For the image with the points (0, 0) and (-2, -2), we have;

(-2 - 0)/(-2 - 0) = 1

Therefore, the slope of the preimage and the image are equal

Therefore, supports Jessie's Claim

2) For a reflection across the line y = 2, we have

We note that the line y = 2 is parallel to the x-axis

For a reflection across the x-axis, for a preimage (x, y), we have the coordinates of the image (x, -y)

However for the reflection across the line y = 2, we have;

For a preimage, (x, y), the coordinate of the image is (x, -y+4)

Given two points, of the preimage (0, 0) and (2, 2), we have the image given as (0, 4) and (2, -2 + 4) = (2, 2);

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (2 - 4)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

3) For a translation up 1.25 units, we note that the difference in the y and x values of the coordinates of the preimage and the image will be equal when finding the slope, and therefore, the slope of the figure of the preimage and the slope of the figure of the image will be equal

Therefore, supports Jessie's Claim

4) For a reflection across the x-axis, a point on the preimage, with coordinates (x, y) will form a point on the image with coordinates (x, - y)

For a preimage with points (0, 0) and (2, 2), we have the image as (0, 0) and (2, -2)

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (-2 - 0)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

6 0
3 years ago
Factor the binomial using its GCF: 10x-15x^4
Igoryamba

Answer:

5x(2 - 3x³)

Step-by-step explanation:

10x-15x^4

The GCF( Greatest Common Factor) of 10x-15x^4 is 5x

Solve:

10x/5x = 2

-15^4/5x = -3x³

Final answer is

5x(2 - 3x³)

                         <u>Check</u>

5x(2 - 3x³)

distribute

5x(2) + 5x(-3x³)

10x - 15x^4

4 0
4 years ago
Read 2 more answers
Hello! Please help me with this. I'm very desperate lol. Its 16. Ill give brainliest
Paladinen [302]

Answer:

You showed the right work and got the right answer!

x = 6

Step-by-step explanation:

Since B is in the middle of A and C, AB + BC = AC

So,

2x - 11 + 8 = x + 3

x - 3 = 3

x = 6

7 0
1 year ago
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