Answer:
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Answer:
Mason has
- 16 20¢ stamps;
- 25 3¢ stamps;
- 40 49¢ stamps.
Step-by-step explanation:
Let x be the number of 20¢ stamps, then the number of 3¢ stamps is x + 9.
Mason has 56 total 49¢ and 20¢ stamps, then the number of 49¢ stamps is 56 - x.
Amounts:
- in 49¢:
cents; - in 20¢:
cents; - in 3¢:
cents.
Total amount:

- $23.55.
Hence,

Mason has
- 16 20¢ stamps;
- 25 3¢ stamps;
- 40 49¢ stamps.
Answer:
or 
Step-by-step explanation:
<u>Step 1: Cross Multiply</u>
<u />


<u>Step 2: Divide both sides by 2.35</u>
<u />
or 
Answer:
or 
Answer:
Step-by-step explanation:
We can rewrite 7 as 3+4 then instead of 3*7 we have 3*(3+4).
Then distribute the 3 in the parenthesis 3*(3+4) = (3*3) + (3*4)
Answer:
Solve for
x
x
by simplifying both sides of the equation, then isolating the variable.
x
≈
0.25181781
Step-by-step explanation: