4•4=16
12•5=60. That’s the answer
For this case we have the following function:

To find the zeros of the function we make
and solve for "x", then:

We multiply by -1 on both sides of the equation:

We factor the equation, for this we look for two numbers that, when multiplied, result in 36 and when added, result in -13. These numbers are -9 and -4.

Thus, the factored equation is:

Therefore, the roots are:

Answer:

Split the second term in 3a^2 - 8a + 4 into two terms
3a^2 - 2a - 6a + 4 = 0
Factor out common terms in the first two terms, then in the last two terms.
a(3a - 2) -2(3a - 2) = 0
Factor out the common term 3a - 2
(3a - 2)(a - 2) = 0
Solve for a;
a = 2/3,2
<u>Answer : B. (2/3,2)</u>