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Marina86 [1]
3 years ago
13

Re-write 18+28 using the distributive property

Mathematics
1 answer:
katovenus [111]3 years ago
3 0
10+8+20+8 I think this is what your asking for
You might be interested in
On the grid draw a scaled copy of quadrilateral ABCD with a scale factor 2/3
Tamiku [17]

Answer:

Attached diagram A'B'C'D'

Step-by-step explanation:

Given is a quadrilateral ABCD. It says to draw a dilated version with a scale factor 2/3.

We see that scale factor is less than 1 which means it shrinks the image to a smaller one.

To draw a scaled copy, we need to find the lengths of its sides.

To do so, we can draw the diagonals AC & BD, and they intersect at origin O(0,0) such that OA= -2, OB= 2, OC= 4, OD= -4.

Applying a scale factor of 2/3, we get OA' = -4/3, OB' = 4/3, OC' = 8/3, OD' = -8/3.

So we have attached a scaled copy A'B'C'D' of quadrilateral ABCD with a scale factor 2/3.

6 0
3 years ago
I need help finding the area
aniked [119]
<h3>Given :</h3>
  • Base of triangle = 7 yd
  • Height of triangle = 10 yd

\\  \\

<h3>To find:</h3>
  • Area of triangle

\\  \\

We know:-

When base and height of triangle is given we use this formula:

\bigstar \boxed{ \rm Area \: of \: triangle =  \frac{base \times height}{2} }

\\  \\

So:-

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{base \times height}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 10}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times2 }{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times\cancel2 }{\cancel2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times1 }{1}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =7 \times 5

\\  \\

\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2}  \\

\\  \\

\therefore  \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} {  \red{\bf{yd} }^{ \red2} }}

\\  \\

<h3>know more :-</h3>

\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}]

7 0
2 years ago
State whether the number 97 is prime, composite, or neither
pickupchik [31]

Answer:

Prime

Step-by-step explanation:

5 0
3 years ago
Is x + 10 a factor of the function f(x) = x3 − 75x + 250? Explain.
lord [1]
Okay, I worked it out and yes, it is a factor. Once you got x=-10, then you plug it into your formula. from there you can work it out like I did and get the answer. You can also input it into a scientific calcuator and figure it out that way. If you need any more help, go ahead and message me. Hope this helps. You can also but it into the box and divide it that way to find out. whichever way is better for you

3 0
3 years ago
Read 2 more answers
12-3 (2w+1)=7w-3 (7+w)
n200080 [17]
12-3(2w+1)=7w-3(7+w) \\ \\ 12-6w-3=7w-21-3w \\ \\ 9-6w=4w-21 \\ \\ -6w-4w=-21-9 \\ \\ -10w=-30 \\ \\ \boxed{x=\frac{-30}{-10}=3}
3 0
3 years ago
Read 2 more answers
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