Average speed
Average speed between the checkpoints
distance between the checkpoints
divided by
time between the checkpoints.
Distance between the checkpoints =
(mileage at B) minus (mileage at A)
=(208)-(120) = 88 miles .
Time between the checkpoints =
time at - time at A
=(3:00 PM) - (1:00 PM) = 2 hours .
Average speed between the checkpoints =
(88 miles) / (2 hours)
=44 miles per hour .
Solution
write the division as a fraction = 12y^4-4y^3 - 6y^2 + 36y - 22 over y-3 multiplied by r over y-3
r ×(2y^4 - 4y^3- 16y^2 + 36y- 22) over (y-3)^2
2ry^4 - 4ry^3 - 16ry^2 + 36ry - 22r over (y-3)^2
I believe the first question is 4 feet / 1 second and the second answer is 16 oz / 1 lb
Answer:
1 : 2
Step-by-step explanation:
this is a 30-60-90 triangle which is a special right triangle. the ratio of the sides is x: x*sqrt(3): 2x, in the order short leg: long leg: hypotenuse. so the ratio of the short leg to the hypotenuse is x:2x or 1:2
Answer:
D. 8/15
Step-by-step explanation:
