Answer:
(1, - 3 )
Step-by-step explanation:
Under a counterclockwise rotation about the origin of 90°
a point (x, y ) → (- y, x ), thus
T(- 3, - 1 ) → T'(1, - 3 )
Answer:
a) there is s such that <u>r>s</u> and s is <u>positive</u>
b) For any <u>r>0</u> , <u>there exists s>0</u> such that s<r
Step-by-step explanation:
a) We are given a positive real number r. We need to wite that there is a positive real number that is smaller. Call that number s. Then r>s (this is equivalent to s<r, s is smaller than r) and s is positive (or s>0 if you prefer). We fill in the blanks using the bold words.
b) The last part claims that s<r, that is, s is smaller than r. We know that this must happen for all posirive real numbers r, that is, for any r>0, there is some positive s such that s<r. In other words, there exists s>0 such that s<r.
The formula for the area of a triangle is (1/2)bh = A
when we plug in the numbers, we get (1/2)(3x-1)x = A
using the distributive property we get (1.5x - .5)x = A
Then its 1.5x^2 - .5x = A
then if we factor out 0.5x we get 0.5x(3x-1) = A
then with the zero product property, 0.5x can equal 0 and x would need to equal 0.
if 3x-1 = 0 , then 3x = 1 then x = 1/3. so our answer would be 1/3 I'm pretty sure because a length cannot be 0
Answer:
is there a picture or can you at least finish the sentence
Step-by-step explanation:
Answer:25 hope this helps
Step-by-step explanation:
