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Dmitry_Shevchenko [17]

3 years ago

14

Cara wants new carpeting for her bedroom. Her bedroom is an 8ft by 6ft rectangle. How much carepeting does she need to nuy to co

ver her entire bedroom floor?

1 answer:

Verizon [17]3 years ago

5 0

48 because length times width you get answer so 8x6=48

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Find the inequality represented by the graph - khan academy<br> PLEASE HELP

Andru [333]

Answer:

y ≤ x - 1

Step-by-step explanation:

The slope is 1 (every unit for x, there is a unit for y, rise/run is 1/1). The y-intercept is -1, because the line crosses the y-axis at -1. The graph is shaded below the line, and the line is solid, meaning that y is less than or equal to x -1, or y ≤ x - 1.

5 0

2 years ago

IM BEGGING SOMEONE PLEASE HELP!!!!

PtichkaEL [24]

Answer:

Option C. y ≤ x-2

y ≤ 50/9-(1/6)x-(1/18)x^2

Step-by-step explanation:

Please, see the attached files.

Thanks.

6 0

3 years ago

Find the inverse g(x)=x/5-6

STALIN [3.7K]

Interpreted: $g(x) = \frac{x}{5} - 6$
Let $y = g(x)$
$y = \frac{x}{5} - 6$
$x = \frac{y}{5} - 6$ (Interchange the x and y-values)

$\frac{y}{5} = x + 6$ (Solve for y)
$y = 5(x + 6)$

$\therefore g^{-1}(x) = 5(x + 6)$

4 0

2 years ago

Which value in this data set is an outlier? 4, 5, 1, 7, 4, 5, 8, 9, 6, 5, 4, 9, 7

omeli [17]

1 is your answer

Note that all the other numbers are inbetween 4 and 9. 1 however, is outside the amount, therefore, your outlier is 1

hope this helps

5 0

3 years ago

Read 2 more answers

The rate at which the temperature is dropping is 6t 5t2 degrees Celsius per hour t hours after sundown. How much had the tempera

Whitepunk [10]

Using a differential equation, it is found that the temperature dropped 72 degrees Celsius between sundown and 3 hours after sundown.

<h3>What is the differential equation that describes the temperature in t hours after sundown?</h3>

The rate at which the temperature is dropping is $6t + 5t^2$ degrees Celsius per hour t hours after sundown, hence the <em>differential equation</em> is:

$\frac{dT}{dt} = 6t + 5t^2$

Applying <em>separation of variables</em>, we find the solution as follows:

$\frac{dT}{dt} = 6t + 5t^2$

$dT = (6t + 5t^2) dt$

$\int dT = \int (6t + 5t^2) dt$

$T(t) = \frac{5t^3}{3} + 3t^2 + T(0)$

In which T(0) is the temperature at sundown.

In 3 hours, the change will be of:

$C = T(3) - T(0) = \frac{5t^3}{3} + 3t^2|_{t = 3}$

Hence:

$\frac{5(3)^3}{3} + 3(3)^2 = 45 + 27 = 72$

The temperature dropped 72 degrees Celsius between sundown and 3 hours after sundown.

You can learn more about differential equations at brainly.com/question/24348029

5 0

2 years ago