All categories

3 years ago

Solve for x. 0.2x – 1.8 5 = 4.2

Mathematics

1 answer:

spin [16.1K]3 years ago

4 0

Answer:

Step-by-step explanation:

0.2x – 1.8/5 = 4.2

0.2x - 1.8 = 4.2 (5)

x =<u> 21 + 1.8 </u>

0.2

x = 22.8 / 0.2

x = 114

You might be interested in

Can someone solve this math problem for me

Alex

Answer:

2x+60=4x-12

60+12=4x-2x

72=2x

x=72/2

x=36.. ans

Step-by-step explanation:

hope this help you

3 0

2 years ago

Find the constant of variation k for the direct variation

Alla [95]

Answer:

The constant of variation is k = -2 ⇒ (B)

Step-by-step explanation:

The equation of the direct variation is y = k x, where

k is the constant of variation

The constant of variation k = $\frac{y}{x}$

The given table has 4 points (-1, 2), (0, 0), (2, -4), (5, -10)

We can use one of the points <em>[except point (0, 0)]</em> to find the value of k

∵ (-1, 2) is a given point

∴ x = -1 and y = 2

∵ k = $\frac{y}{x}$

→ Substitute the values of x and y in the relation above

∴ k = $\frac{2}{-1}$

∴ k = -2

The constant of variation is k = -2

7 0

3 years ago

In an hyperbola, the fixed points that have a constant difference in distance from the center are called _

Juli2301 [7.4K]

Answer is C. Foci...

5 0

2 years ago

A large high school offers AP Statistics and AP Calculus Among the seniors in this school 65% take AP Statistics, 45% take AP Ca

Igoryamba

Answer:

0.8

Step-by-step explanation:

P(AP statistics) = 65%

P(AP Calculus) = 45%

P(AP statistics n AP Calculus) = 30%

Probability of AP statistics or AP Calculus but not both :

Probability of event A or B :

P(AUB) = p(A) + p(B) - p(AnB)

P(AP statistics U AP Calculus) = P(AP statistics) + P(AP Calculus) - P(AP statistics n AP Calculus)

= 0.65 + 0.45 - 0.30

= 0.8

= 80%

4 0

2 years ago

Calculus 3 chapter 16

o-na [289]

Evaluate $\vec F$ at $\vec r$ :

$\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k$

Compute the line element $d\vec r$ :

$d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt$

Simplifying the integrand, we have

$\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt$

Then the line integral evaluates to

$\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}$

3 0

1 year ago

Solve for x. 0.2x – 1.8 5 = 4.2​

Solve for x. 0.2x – 1.8 5 = 4.2