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Artyom0805 [142]
3 years ago
9

A share of Orange stock that was worth $25 in 2000 increased exponentially to $72 in 2010. What is the annual multiplier and wha

t is the annual percent increase?
Mathematics
1 answer:
umka21 [38]3 years ago
6 0
\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\stackrel{multiplier}{\textit{initial amount}}\\
r=\stackrel{increase~rate}{rate\to r\%\to \frac{r}{100}}\\
t=\textit{elapsed time}\\
\end{cases}\\\\
-------------------------------

\bf \textit{we know that in }\stackrel{year~0}{2000}\textit{ there were }\stackrel{A}{\$25}\implies 25=I(1+r)^0
\\\\\\
25=I(1)\implies 25=I\qquad \qquad \boxed{A=25(1+r)^t}\\\\
-------------------------------\\\\
\textit{we also know that in }\stackrel{year~10}{2010}\textit{ it turned to }\stackrel{A}{72}\implies 72=25(1+r)^{10}

\bf \cfrac{72}{25}=(1+r)^{10}\implies \sqrt[10]{\frac{72}{25}}=1+r\implies \sqrt[10]{\frac{72}{25}}-1=r
\\\\\\
0.111576\approx r\implies r\%=100\cdot 0.111576\implies r\approx \stackrel{\%}{11.1576}
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2x−7+10=−2
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Step 2: Subtract 3 from both sides.
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Answer:
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Natalija [7]

Answer:

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Step-by-step explanation:

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Length of the segment between B(9, 2) and C(9, -3) = \sqrt{(9-9)^2+(2+3)^2}

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Length of the segment between C(9, -3) and D(2, -3) = \sqrt{(9-2)^2+(-3+3)^2}

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