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lana [24]
3 years ago
9

So I need help finding the cross section of all the shapes, so any cross section experts mind helping?

Mathematics
1 answer:
Kisachek [45]3 years ago
3 0

Answer:

Since this is old, im just gonna get these points, don't wan't them to go to waste lm.ao

Step-by-step explanation:

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What is the reason for statement 7 in the given proof?
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Answer: definition of slope

Step-by-step explanation:

The results in step 7 come from substituting the coordinates into the slope formula.

5 0
2 years ago
Simplify 7 - 2(5 - 2x) -10x + 25 -4x - 3
Kisachek [45]

Hi,

Let's simplify this equation step-by-step.

7−2(5−2x)−10x+25−4x−3

Distribute:

=7+(−2)(5)+(−2)(−2x)+−10x+25+−4x+−3

=7+−10+4x+−10x+25+−4x+−3

Combine Like Terms:

=7+−10+4x+−10x+25+−4x+−3

=(4x+−10x+−4x)+(7+−10+25+−3)

=−10x+19

Answer:

=−10x+19

Have a great day!

8 0
3 years ago
Read 2 more answers
Which blocks have a volume between 20 and 30 cubic centimeters?
Artyom0805 [142]

Answer: c

Step-by-step explanation:

7 0
3 years ago
A person is standing 50 ft from a statue. The person looks up at an angle of elevation of 8 degrees when staring at the top of t
borishaifa [10]

The height of the statue is 19.5 feet.

Why?

We can solve the problem using trigonometric formulas. In this case, we are going to use the trigonometric formula of the tangent.

We know that the person is standing 50ft from the statue, so, it will be the base of the two triangles formed by both angles (elevation and depression)

Using the trignometric formula, we have:

First triangle:

tg(\alpha )=\frac{h_{1}}{base} \\\\tg(8\°)=\frac{h_{1}}{50ft}\\\\0.14*50ft=h_1\\\\h_1=7ft

Second triangle:

tg(\alpha )=\frac{h_{2}}{base} \\\\tg(14\°)=\frac{h_{1}}{50ft}\\\\0.25*50ft=h_1\\\\h_1=12.5ft

Now, the total height of the statue will be:

TotalHeight=h_1+h_2=7ft+12.5ft\\\\TotalHeight=19.5ft

Have a nice day!

8 0
3 years ago
W over 3< 1 or 3w+5>11
s344n2d4d5 [400]

Step-by-step explanation:

\dfrac{w}{3}6\qquad\text{divide both sides by 3}\\\\\dfrac{3w}{3}>\dfrac{6}{3}\\\\w>2\\\\

\text{If is}\ \bold{OR},\ \text{then}:\\\\w2\Rightarrow w\in\mathbb{R}\ /\text{any real number/}\\\\\text{If there is a mistake, and it should be}\ \bold{AND},\ \text{then}:\\\\w2\Rightarrow 2

4 0
3 years ago
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