Your money grows faster because the interest is added back into the principle and then the next time it compounds you get interest on the new principle amount. So for example, you deposit $100 in an account that gets 5% interest compounded semiannually. The first time it compounds you get $5 added to your account so your new balance is $105. The next time it compounds you get 5% on $105 so you get $5.25 added and so on. If this is only happening semi-annually that would be all you get for the year. But if it happens quarterly you would get would get deposits of $5.51 and $5.79 as well. If it compounds monthly or even daily your money would grow more and more. Hope this helps.
Answer:
a) w = 8; y = 5.25
b) x = 10; z = 7.2
Step-by-step explanation:
a) Dimensions on the smaller figure are FA/F'A' = 3/4 times those on the larger figure.
6 = (3/4)w
w = 24/3 = 8
y = (3/4)·7 = 21/4 = 5.25
__
b) Dimensions on the smaller figure are ER/E'R' = 9/15 = 3/5 times those on the larger figure.
6 = (3/5)x
x = 30/3 = 10
z = (3/5)12 = 36/5 = 7.2
Answer:A
Step-by-step explanation:
23/50= 0.46 *100= 46%
Answer:
Radius = 21
Step-by-step explanation:
Volume of a sphere = 4/3 * pie * radius^3
12,348 pie = 4/3 * pie * radius ^3
12,348 = 4/3 * radius^3
(12,348 * 3)/ 4 = radius^3
9261 = radius^3
radius = ![\sqrt[3]{9261}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9261%7D)
radius = 21
Answer:
Step-by-step explanation:
Hello!
X: number of absences per tutorial per student over the past 5 years(percentage)
X≈N(μ;σ²)
You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.
The formula for the CI is:
X[bar] ±
* 
⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.
Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4
X[bar]= 10.41
S= 3.71

[10.41±1.645*
]
[9.26; 11.56]
Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.
I hope this helps!