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3 years ago

A rectangle with an area of 16 square units?

Mathematics

1 answer:

NeX [460]3 years ago

5 0

Answer:

Area of a rectangle equals length x width soooo

The side lengths should be 2 and 8 since they are what equals 16

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3 years ago

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How to expand 3(2t+1)

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Hey there :)

3 ( 2t + 1 )
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3 ( 2t ) + 3 ( 1 )

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3 years ago

For the graphed function f(x) = (2)x + 2 + 1, calculate the average rate of change from x = −1 to x = 0. a graph of an exponenti

Paladinen [302]

Answer:

2 is the average rate of change of the function $f(x)=2^{x+2}+1$ from $x=-1$ to $x=0$ .

Step-by-step explanation:

I assume you meant $f(x)=2^{x+2}+1$ based off the points.

We are given that $(-1,3)$ and $(0,5)$ are points on this curve.

We are asked to find the average rate of change (the slope) from $x=-1$ to $x=0$ .

We have the two points needed to find the slope.

We just need to line them up and subtract vertically then put 2nd difference on top of 1st difference.

$(-1,3)$

$(0,5)$

--------------------Subtracting!

$-1,-2$

So the slope is $\frac{-2}{-1}=2$ .

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3 years ago

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Find the particular solution to y ' = 4sin(x) given the general solution is y = c - 4cos(x) and the initial condition y of pi ov

Lana71 [14]

The general solutions always have some additive/multiplicative constant, that you must fix in the particular solution.

In order to do so, you need to impose that the particular solution passes through a certain point. In your case, you have

$y(x) = c-4\cos(x)$

and you want

$y\left(\dfrac{\pi}{2}\right) = 2$

Put everything together, and you have

$y\left(\dfrac{\pi}{2}\right) = c-4\cos\left(\dfrac{\pi}{2}\right) = c = 2$

Since the cosine is zero in the chosen point. So, we've fixed the value of the constant, and the particular solution is found:

$y(x) = 2-4\cos(x)$

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3 years ago